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Question

If m:f = 16:3, then what is the value of \(\frac{3m-16f}{3m+16f}\) ?

This question was previously asked in
RRB ALP 2025 CBT 2 Wiremen Question Paper (28-Jul-2026) (Shift 2)
The correct answer is
$0$

Ratio Algebra: Simplifying the Expression

The problem asks for the value of the expression \( \frac{3m-16f}{3m+16f} \) given that the ratio \(m:f = 16:3\).

Using Ratios for Simplification

From the given ratio \(m:f = 16:3\), we can express \(m\) in terms of \(f\) or vice-versa. A common method is to assume:

  • \(m = 16k\)
  • \(f = 3k\)

where \(k\) is a non-zero constant.

Substituting Values into the Expression

Now, substitute these values into the expression \(\frac{3m-16f}{3m+16f}\):

  • Numerator: \(3m - 16f = 3(16k) - 16(3k)\)
  • Denominator: \(3m + 16f = 3(16k) + 16(3k)\)

Calculation Steps

  1. Calculate the numerator: \( 3(16k) - 16(3k) = 48k - 48k = 0 \)
  2. Calculate the denominator: \( 3(16k) + 16(3k) = 48k + 48k = 96k \)
  3. Form the fraction: \( \frac{0}{96k} \)
  4. Simplify the fraction. Since \(k \neq 0\), the value is: \( 0 \)

Therefore, the value of the expression \(\frac{3m-16f}{3m+16f}\) is 0.

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