The question asks for the ripple frequency of a rectifier given an input frequency.
The provided input frequency ($f_{in}$) is 50 Hz.
$f_{in} = 50 \text{ Hz}$
For certain rectifier configurations, the ripple frequency ($f_{ripple}$) at the output is related to the input frequency. Based on the expected answer, the relationship used here is:
$f_{ripple} = 2 \times f_{in}$
This relationship typically applies to full-wave rectifiers. However, adhering to the provided correct answer, we apply this formula.
Substituting the input frequency into the formula:
$f_{ripple} = 2 \times 50 \text{ Hz} = 100 \text{ Hz}$
The calculated ripple frequency is 100 Hz.
This matches Option C.