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Question

If \(\cos x = \frac{5}{{13}}\) , x lies in the fourth quadrant, and determines the value of the other five trigonometric functions?

The correct answer is \({\mathop{\rm Sec}\nolimits}\ x = \frac{{13}}{5},\sin x =- \frac{{12}}{{13}},\rm cosec\ x =- \frac{{13}}{{12}},\tan x = -\frac{{12}}{5},\cot x =- \frac{5}{{12}}\)

To determine the values of the other five trigonometric functions when \(\cos x = \frac{5}{{13}}\) and \(x\) lies in the fourth quadrant, we will use fundamental trigonometric identities and rules specific to quadrants.

Understanding Quadrants and Signs:

  • In the fourth quadrant, the angle \(x\) is between \(270^\circ\) and \(360^\circ\) (or \(\frac{3\pi}{2}\) and \(2\pi\) radians).
  • In this quadrant, the cosine function (\(\cos x\)) and its reciprocal, the secant function (\(\sec x\)), are positive.
  • All other trigonometric functions, namely sine (\(\sin x\)), tangent (\(\tan x\)), cosecant (\(\csc x\)), and cotangent (\(\cot x\)), are negative in the fourth quadrant.

Trigonometric Functions Calculation

Given: \(\cos x = \frac{5}{{13}}\)

Sine Function: Determining \(\sin x\)

We use the fundamental trigonometric identity: \(\sin^2 x + \cos^2 x = 1\)

Substitute the given value of \(\cos x\):

\[\sin^2 x + \left(\frac{5}{13}\right)^2 = 1\] \[\sin^2 x + \frac{25}{169} = 1\] \[\sin^2 x = 1 - \frac{25}{169}\] \[\sin^2 x = \frac{169 - 25}{169}\] \[\sin^2 x = \frac{144}{169}\]

Taking the square root of both sides:

\[\sin x = \pm \sqrt{\frac{144}{169}}\] \[\sin x = \pm \frac{12}{13}\]

Since \(x\) lies in the fourth quadrant, the value of \(\sin x\) must be negative.

Therefore, \[\sin x = -\frac{12}{13}\]

Secant Function: Determining \(\sec x\)

The secant function is the reciprocal of the cosine function:

\[\sec x = \frac{1}{\cos x}\]

Substitute the given value of \(\cos x\):

\[\sec x = \frac{1}{\frac{5}{13}}\]

Therefore, \[\sec x = \frac{13}{5}\]

This result is positive, which is consistent with the rules for the fourth quadrant.

Tangent Function: Determining \(\tan x\)

The tangent function is the ratio of sine to cosine:

\[\tan x = \frac{\sin x}{\cos x}\]

Substitute the values of \(\sin x\) and \(\cos x\):

\[\tan x = \frac{-\frac{12}{13}}{\frac{5}{13}}\] \[\tan x = -\frac{12}{5}\]

This result is negative, which is consistent with the rules for the fourth quadrant.

Cosecant Function: Determining \(\csc x\)

The cosecant function is the reciprocal of the sine function:

\[\csc x = \frac{1}{\sin x}\]

Substitute the value of \(\sin x\):

\[\csc x = \frac{1}{-\frac{12}{13}}\]

Therefore, \[\csc x = -\frac{13}{12}\]

This result is negative, which is consistent with the rules for the fourth quadrant.

Cotangent Function: Determining \(\cot x\)

The cotangent function is the reciprocal of the tangent function:

\[\cot x = \frac{1}{\tan x}\]

Substitute the value of \(\tan x\):

\[\cot x = \frac{1}{-\frac{12}{5}}\]

Therefore, \[\cot x = -\frac{5}{12}\]

This result is negative, which is consistent with the rules for the fourth quadrant.

Summary of Trigonometric Values

Here is a summary of all six trigonometric function values for the given angle \(x\):

Function Value
\(\cos x\) \(\frac{5}{13}\)
\(\sin x\) \(-\frac{12}{13}\)
\(\sec x\) \(\frac{13}{5}\)
\(\csc x\) \(-\frac{13}{12}\)
\(\tan x\) \(-\frac{12}{5}\)
\(\cot x\) \(-\frac{5}{12}\)

Based on our calculations, the values for the other five trigonometric functions are:

\(\sec x = \frac{{13}}{5},\sin x =- \frac{{12}}{{13}},\rm cosec\ x =- \frac{{13}}{{12}},\tan x = -\frac{{12}}{5},\cot x =- \frac{5}{{12}}\)

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Important Questions from Trigonometric Ratios

  1. If $\sin\theta = \frac{p^2 - 1}{p^2 + 1}$, and $\theta$ is an acute angle, then find the value of $\cos\theta$.
  2. Let ABC be a right-angled triangle such that $\angle B = 90^\circ$, AB = 12 cm and AC = 13 cm. Find the value of $\tan A - \cot C$.
  3. What is \(\tan \alpha + \tan \beta\) equal to?

  4. If \(\cos\theta = 24/25\) then \(\cot\theta\) will be
  5. Value of \(\sin 60^\circ / \cos 60^\circ\)
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