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Question

If a memory partition of size 80k is allocated to a process of size 60k then the 20k of the partition is wasted and cannot be allocated to any process. It is called _______.

The correct answer is

internal fragmentation

Understanding Memory Fragmentation in Operating Systems

When an operating system manages memory, it divides the memory into partitions or blocks to allocate to different processes. However, this allocation process can sometimes lead to wasted space, which is known as memory fragmentation. There are primarily two types of fragmentation: internal and external fragmentation.

Analyzing the Given Scenario

The question describes a specific situation:

  • A memory partition of size 80k is available.
  • A process requiring 60k of memory is allocated to this partition.
  • The difference in size, 80k - 60k = 20k, is left unused within this allocated partition.

This 20k of wasted space is part of the 80k block that was assigned to the 60k process. Because this space is inside the allocated block and not available for other processes, it represents a particular type of fragmentation.

Types of Memory Fragmentation

Let's look at the relevant types of fragmentation:

  • Internal Fragmentation: This occurs when a memory partition allocated to a process is larger than the process's actual size. The excess space within the partition cannot be used by any other process and remains idle. The 20k wasted space in the described scenario fits this definition perfectly.
  • External Fragmentation: This occurs when there is enough total free space in memory to satisfy a request, but the free space is divided into many small, non-contiguous blocks. A process requiring a large contiguous block cannot be allocated even though the total free memory is sufficient. This is a problem of scattered free space, not wasted space *within* an allocated block.

Memory Allocation Strategies (Worst Fit and Best Fit)

Options 2 and 3 refer to memory allocation strategies, not types of fragmentation:

  • Worst Fit: This strategy allocates the process to the largest available free memory partition. While it might leave a larger leftover block, it is still a strategy for choosing a partition, not a type of fragmentation itself.
  • Best Fit: This strategy allocates the process to the smallest available free memory partition that is large enough to hold the process. This strategy aims to minimize the leftover internal fragmentation within each allocated partition, but it can lead to more numerous, smaller free blocks, potentially increasing external fragmentation.

Neither worst fit nor best fit is the name for the fragmentation itself; they are methods used by the operating system to try and manage or minimize fragmentation.

Conclusion on the Wasted Space

Based on the definitions, the 20k of wasted space within the 80k partition allocated to the 60k process is classic internal fragmentation. The operating system allocated a fixed-size block (or a block rounded up to a certain size) to the process, and the unused space inside this block is the internal fragmentation.

Therefore, the correct term for the wasted 20k within the 80k partition is internal fragmentation.

Revision Table: Key Memory Concepts

Concept Description Example Scenario
Internal Fragmentation Wasted space within an allocated memory block because the block is larger than the process size. Allocating an 80k partition for a 60k process.
External Fragmentation Total free space is sufficient, but it's broken into non-contiguous blocks, preventing allocation of a large contiguous process. Memory has 100k free space in blocks of 20k, 30k, 50k, but a process needs 60k contiguous space.
Worst Fit Memory allocation strategy: Allocate the process to the largest available free partition. Choosing an 80k free block for a 10k process when 30k and 50k blocks are also available.
Best Fit Memory allocation strategy: Allocate the process to the smallest available free partition that fits. Choosing a 30k free block for a 25k process when 50k and 80k blocks are also available.

Additional Information on Memory Management

Understanding memory management is crucial in operating systems. Fragmentation is a significant challenge that affects system performance.

  • Causes of Internal Fragmentation: Often occurs in systems that allocate memory in fixed-size blocks or pages. Processes might not perfectly fit into these block sizes.
  • Solutions for Internal Fragmentation: Paging can help reduce internal fragmentation by dividing processes and memory into smaller, fixed-size units (pages and frames). However, a small amount of internal fragmentation can still occur in the last page. Dynamic partition allocation can also reduce it compared to static partitions, but internal fragmentation can still occur due to block size rounding or alignment requirements.
  • Causes of External Fragmentation: Caused by dynamic allocation and deallocation of memory blocks of varying sizes over time, leaving gaps between allocated blocks.
  • Solutions for External Fragmentation:
    • Compaction: Moving all allocated memory blocks together to form one large contiguous free space. This is computationally expensive.
    • Paging: Eliminates external fragmentation by allocating non-contiguous physical frames to a process's logical pages.
    • Segmentation: Allows programs to be divided into logical segments, which can be loaded into non-contiguous memory areas. Can still suffer from external fragmentation.

Choosing the right memory management technique and allocation strategy is essential for minimizing fragmentation and maximizing memory utilization.

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Important Questions from Non Contiguous

  1. If main memory access time is 400 μs, TLB access time is 50 μs, considering TLB hit as 90%, what will be the overall access time?  

  2. Which of the following is NOT a base of product related segmentation?

  3. The purpose of a page table in a paging system is to:

  4. Consider a single-level page table system. with the page table stored in the memory. If the hit rate to TLB is 80%, and it takes 15 nanoseconds to search the TLB. and 150 nanoseconds to access the main memory, then what is the effective memory access time, in nanoseconds ?

  5. Dirty bit is used to show the

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