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Question

Consider a single-level page table system. with the page table stored in the memory. If the hit rate to TLB is 80%, and it takes 15 nanoseconds to search the TLB. and 150 nanoseconds to access the main memory, then what is the effective memory access time, in nanoseconds ?

The correct answer is

195

A TLB hit costs 15 + 150 = 165 ns. A miss costs 15 + 150 + 150 = 315 ns: one access reads the page table and another reads the data.

\(\mathrm{EAT}=0.8(165)+0.2(315)=195\text{ ns}.\)

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Important Questions from Non Contiguous

  1. If a memory partition of size 80k is allocated to a process of size 60k then the 20k of the partition is wasted and cannot be allocated to any process. It is called _______.

  2. If main memory access time is 400 μs, TLB access time is 50 μs, considering TLB hit as 90%, what will be the overall access time?  

  3. Which of the following is NOT a base of product related segmentation?

  4. The purpose of a page table in a paging system is to:

  5. Dirty bit is used to show the

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