If a bulb is designed to work at 12 volts and 0.5 amperes, what should be the resistance of the filament according to Ohm's Law?
24 ohms
Ohm's Law states that \(V = IR\), so the resistance of the filament is \(R = V/I\).
Substituting the rated values: \(R = 12\,\text{V} \div 0.5\,\text{A} = 24\,\Omega\).
Hence, the resistance of the bulb's filament is 24 ohms.
Hence, 24 ohms.
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