This problem involves finding an angle within a circle given other angles related to the center and points on the circumference. We are given a circle with center O and three points A, B, and C on its circumference. We know the central angles subtended by the arcs AB and BC: $\angle AOB = 90^\circ$ and $\angle BOC = 120^\circ$. We need to find the measure of the inscribed angle $\angle ABC$.
To solve this, we use a fundamental theorem in circle geometry:
1. Identify the arcs: We are given angles related to arcs AB and BC.
2. Determine the arrangement of points: Assuming the points A, B, and C are arranged consecutively around the circle, we can find the measure of the arc AC that passes through B.
3. Find the measure of the arc AC not containing B: The angle $\angle ABC$ subtends the arc AC that *does not* contain the point B. The measure of the entire circle is $360^\circ$.
4. Calculate the central angle $\angle AOC$: The central angle subtending the minor arc AC is $\angle AOC$. Its measure is equal to the measure of the minor arc AC.
5. Calculate the inscribed angle $\angle ABC$: Now, we apply the theorem relating the central angle and the inscribed angle subtending the same arc.
Therefore, the measure of angle $\angle ABC$ is $75^\circ$. This corresponds to the second option provided.
In a circle, a ten cm long chord is at a distance of 12 cm from the centre of the circle. The length of the diameter of the circle (in cm) is:
Chord AB of a circle of radius 10 cm is at a distance 8 cm from the centre O. If tangents drawn at A and B intersect at P., then the length of the tangent AP (in cm) is:
A chord 21 cm long is drawn in a circle of diameter 25 cm. The perpendicular distance of the chord from the centre is:
In a circle with radius 5 cm, a chord is at a distance of 3 cm from the centre. The length of the chord is:
O is the centre of this circle. Tangent drawn from a point P, touches the circle at Q. If PQ = 24 cm and OQ = 10 cm, then what is the value of OP?