This problem involves finding an angle within a circle given other angles related to the center and points on the circumference. We are given a circle with center O and three points A, B, and C on its circumference. We know the central angles subtended by the arcs AB and BC: $\angle AOB = 90^\circ$ and $\angle BOC = 120^\circ$. We need to find the measure of the inscribed angle $\angle ABC$.
To solve this, we use a fundamental theorem in circle geometry:
1. Identify the arcs: We are given angles related to arcs AB and BC.
2. Determine the arrangement of points: Assuming the points A, B, and C are arranged consecutively around the circle, we can find the measure of the arc AC that passes through B.
3. Find the measure of the arc AC not containing B: The angle $\angle ABC$ subtends the arc AC that *does not* contain the point B. The measure of the entire circle is $360^\circ$.
4. Calculate the central angle $\angle AOC$: The central angle subtending the minor arc AC is $\angle AOC$. Its measure is equal to the measure of the minor arc AC.
5. Calculate the inscribed angle $\angle ABC$: Now, we apply the theorem relating the central angle and the inscribed angle subtending the same arc.
Therefore, the measure of angle $\angle ABC$ is $75^\circ$. This corresponds to the second option provided.
A chord 21 cm long is drawn in a circle of diameter 25 cm. The perpendicular distance of the chord from the centre is:
AB is a chord of a circle with centre O and P is any point on the circle. If ∠APB = 112°, then what is the measure of ∠OAB ?
In a circle with radius 5 cm, a chord is at a distance of 3 cm from the centre. The length of the chord is:
The distance between the centres of two circles is 24 cm. If the radius of the two circles are 4 cm and 8 cm, then what is the sum of the lengths (in cm) of the direct common tangent and the transverse common tangent?
An equilateral triangle ABC and a scalene triangle DBC are inscribed in a circle on same side of the arc. what is ∠BDC equal to?