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Question

If a = 17,b = 13, then find the value of the expression (a3 - b3 - 3a2b + 3ab2).

This question was previously asked in
SSC CGL 2023 (Tier-II) Paper 1 Previous Year Paper (26-Oct-2023) (Shift-1)
The correct answer is

64

Evaluating the Algebraic Expression \( (a^3 - b^3 - 3a^2b + 3ab^2) \)

The question asks us to find the value of the expression \( (a^3 - b^3 - 3a^2b + 3ab^2) \) when \( a = 17 \) and \( b = 13 \).

Let's look at the given expression:

\( a^3 - b^3 - 3a^2b + 3ab^2 \)

We can rearrange the terms in this expression:

\( a^3 - 3a^2b + 3ab^2 - b^3 \)

This rearranged form looks very familiar. It is the expansion of a common algebraic identity.

Recognizing the Algebraic Identity

Recall the identity for the cube of a difference:

\( (x - y)^3 = x^3 - 3x^2y + 3xy^2 - y^3 \)

Comparing our rearranged expression \( a^3 - 3a^2b + 3ab^2 - b^3 \) with the expansion of \( (x - y)^3 \), we can see that if we replace \( x \) with \( a \) and \( y \) with \( b \), we get exactly the given expression.

Therefore, the expression \( (a^3 - b^3 - 3a^2b + 3ab^2) \) is equal to \( (a - b)^3 \).

Substituting the Given Values

We are given that \( a = 17 \) and \( b = 13 \). Now we need to substitute these values into the simplified expression \( (a - b)^3 \).

First, calculate the value of \( (a - b) \):

\( a - b = 17 - 13 \)

\( a - b = 4 \)

Now, cube this result:

\( (a - b)^3 = (4)^3 \)

Calculating the Final Value

To calculate \( 4^3 \), we multiply 4 by itself three times:

\( 4^3 = 4 \times 4 \times 4 \)

\( 4 \times 4 = 16 \)

\( 16 \times 4 = 64 \)

So, the value of the expression \( (a^3 - b^3 - 3a^2b + 3ab^2) \) when \( a = 17 \) and \( b = 13 \) is 64.

Here is a summary of the steps:

  1. Identify the given expression: \( a^3 - b^3 - 3a^2b + 3ab^2 \).
  2. Rearrange the terms: \( a^3 - 3a^2b + 3ab^2 - b^3 \).
  3. Recognize the algebraic identity: \( (a - b)^3 = a^3 - 3a^2b + 3ab^2 - b^3 \).
  4. Equate the expression to the identity: \( (a^3 - b^3 - 3a^2b + 3ab^2) = (a - b)^3 \).
  5. Substitute the values \( a = 17 \) and \( b = 13 \).
  6. Calculate \( a - b = 17 - 13 = 4 \).
  7. Calculate \( (a - b)^3 = 4^3 \).
  8. Compute the cube: \( 4^3 = 64 \).

Revision Table: Key Algebraic Identities

Understanding common algebraic identities is crucial for simplifying expressions.

Identity Name Identity Formula
Square of a Sum \( (x+y)^2 = x^2 + 2xy + y^2 \)
Square of a Difference \( (x-y)^2 = x^2 - 2xy + y^2 \)
Difference of Squares \( x^2 - y^2 = (x+y)(x-y) \)
Cube of a Sum \( (x+y)^3 = x^3 + 3x^2y + 3xy^2 + y^3 \)
Cube of a Difference \( (x-y)^3 = x^3 - 3x^2y + 3xy^2 - y^3 \)
Sum of Cubes \( x^3 + y^3 = (x+y)(x^2 - xy + y^2) \)
Difference of Cubes \( x^3 - y^3 = (x-y)(x^2 + xy + y^2) \)

Additional Information: Importance of Identities in Algebra

Algebraic identities are equations that are true for all possible values of the variables involved. They are powerful tools in algebra because they help in:

  • Simplifying complex algebraic expressions.
  • Solving equations more easily.
  • Factoring polynomials.
  • Performing calculations quickly, as seen in this problem where calculating \( (17-13)^3 \) is much simpler than calculating \( 17^3 - 13^3 - 3 \times 17^2 \times 13 + 3 \times 17 \times 13^2 \).

Recognizing the structure of an expression and matching it to a known identity is a key skill in algebra. In this problem, identifying the expression as \( (a-b)^3 \) allowed for a straightforward calculation.

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Important Questions from Identities

  1. (x - y) 3+ (y - z) 3+ (z - x) 3= ?

  2. If   \(x + \left( {\frac{1}{x}} \right) = 12\)  and  \({x^2} - \frac{1}{{{x^2}}} = 50\) , then the value of  \({x^4} - \frac{1}{{{x^4}}} \)  is:

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