If 3.96 cubic dm of lead is to be drawn in to a cylindrical wire of diameter 0.6 cm, then the length of the wire (in metres), is:
140 m
This problem involves the concept of volume conservation. When a material like lead is melted and drawn into a different shape, its total volume remains constant. We are given the volume of lead in cubic decimetres (dm³) and the diameter of the cylindrical wire it is drawn into in centimetres (cm). We need to find the length of the wire in metres (m).
First, we need to work with consistent units. The diameter is given in centimetres (cm), and the volume is in cubic decimetres (dm³). Let's convert the volume from cubic decimetres to cubic centimetres (cm³). We know that 1 decimetre (dm) is equal to 10 centimetres (cm).
So, 1 cubic decimetre ($1 \text{ dm}^3$) is equal to $(10 \text{ cm})^3$.
$1 \text{ dm}^3 = 10 \text{ cm} \times 10 \text{ cm} \times 10 \text{ cm} = 1000 \text{ cm}^3$
Now, convert the given volume of lead:
Volume of lead = $3.96 \text{ dm}^3 = 3.96 \times 1000 \text{ cm}^3 = 3960 \text{ cm}^3$
The diameter of the cylindrical wire is 0.6 cm. The radius ($r$) is half of the diameter.
$r = \frac{\text{Diameter}}{2} = \frac{0.6 \text{ cm}}{2} = 0.3 \text{ cm}$
The volume of a cylinder is given by the formula:
$V = \pi r^2 L$
Where $V$ is the volume, $r$ is the radius, and $L$ is the length (or height) of the cylinder.
In this problem, the volume of the cylindrical wire is equal to the volume of the lead used, which is 3960 cm³. We know the radius is 0.3 cm. We need to find the length $L$ in centimetres first.
Substitute the known values into the formula:
$3960 \text{ cm}^3 = \pi (0.3 \text{ cm})^2 L$
$3960 = \pi (0.09) L$
We can use the value of $\pi \approx \frac{22}{7}$ for calculation.
$3960 = \frac{22}{7} \times 0.09 \times L$
To find $L$, rearrange the equation:
$L = \frac{3960 \times 7}{22 \times 0.09}$
To simplify the calculation, multiply the numerator and denominator by 100 to remove the decimal from 0.09:
$L = \frac{3960 \times 7 \times 100}{22 \times 0.09 \times 100} = \frac{3960 \times 7 \times 100}{22 \times 9}$
Now, perform the divisions:
$3960 \div 9 = 440$
$440 \div 22 = 20$
So, $L = 20 \times 7 \times 100$
$L = 140 \times 100$
$L = 14000 \text{ cm}$
The length is currently in centimetres. We need to convert it to metres. We know that 1 metre (m) = 100 centimetres (cm).
To convert centimetres to metres, divide by 100:
$L \text{ in metres} = \frac{14000 \text{ cm}}{100 \text{ cm/m}}$
$L \text{ in metres} = 140 \text{ m}$
Thus, the length of the wire is 140 metres.
| Quantity | Value | Unit |
|---|---|---|
| Initial Volume of Lead | 3.96 | dm³ |
| Volume of Lead (converted) | 3960 | cm³ |
| Diameter of Wire | 0.6 | cm |
| Radius of Wire | 0.3 | cm |
| Volume of Wire ($ \pi r^2 L $) | 3960 | cm³ |
| Calculated Length (L) | 14000 | cm |
| Final Length (converted) | 140 | m |
The length of the cylindrical wire is 140 metres.
| Concept | Description | Formula/Relation |
|---|---|---|
| Volume Conservation | The total volume of a material remains constant when its shape changes. | $ V_{initial} = V_{final} $ |
| Volume of Cylinder | Space occupied by a cylinder. | $ V = \pi r^2 h $ (or $ \pi r^2 L $ for length) |
| dm³ to cm³ Conversion | Converting cubic decimetres to cubic centimetres. | $ 1 \text{ dm}^3 = 1000 \text{ cm}^3 $ |
| cm to m Conversion | Converting centimetres to metres. | $ 1 \text{ m} = 100 \text{ cm} $ |
Calculating volumes is essential in various real-world applications, especially in manufacturing and engineering. For example:
Problems like converting the volume of lead into a wire length are practical examples of how geometry and volume calculations are used in material science and manufacturing processes like wire drawing.
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