A solid cylinder has a radius of 9 cm and a height of 25 cm. What is the ratio of its total surface area to its curved surface area?
34 : 25
This question asks for the ratio of the total surface area to the curved surface area of a solid cylinder with given dimensions. A solid cylinder has three surfaces: the curved surface and two circular bases.
To solve this, we need to recall the formulas for the surface areas of a cylinder:
The curved surface area of a cylinder is the area of the side that curves around. The formula is given by:
\(\text{CSA} = 2 \pi r h\)
Where:
Given radius \(r = 9\) cm and height \(h = 25\) cm, we can calculate the CSA:
\(\text{CSA} = 2 \times \pi \times 9 \times 25\)
\(\text{CSA} = 18 \times 25 \times \pi\)
\(\text{CSA} = 450 \pi\) sq cm
The total surface area of a solid cylinder includes the curved surface area and the area of the two circular bases. The area of each circular base is \(\pi r^2\). So, the total surface area is:
\(\text{TSA} = \text{Curved Surface Area} + \text{Area of two bases}\)
\(\text{TSA} = 2 \pi r h + 2 \pi r^2\)
Alternatively, we can factor out \(2 \pi r\):
\(\text{TSA} = 2 \pi r (h + r)\)
Using the given radius \(r = 9\) cm and height \(h = 25\) cm:
\(\text{TSA} = 2 \times \pi \times 9 \times (25 + 9)\)
\(\text{TSA} = 18 \pi \times (34)\)
\(\text{TSA} = 612 \pi\) sq cm
The question asks for the ratio of TSA to CSA, which is \(\frac{\text{TSA}}{\text{CSA}}\).
\(\text{Ratio} = \frac{612 \pi}{450 \pi}\)
We can cancel out \(\pi\) from the numerator and the denominator:
\(\text{Ratio} = \frac{612}{450}\)
Now, we simplify the fraction by finding common factors. Both numbers are divisible by 2:
\(\frac{612 \div 2}{450 \div 2} = \frac{306}{225}\)
Both numbers are divisible by 3:
\(\frac{306 \div 3}{225 \div 3} = \frac{102}{75}\)
Both numbers are divisible by 3 again:
\(\frac{102 \div 3}{75 \div 3} = \frac{34}{25}\)
The simplified ratio is \(34 : 25\).
We can also find the ratio directly using the formulas before substituting values:
\(\text{Ratio} = \frac{\text{TSA}}{\text{CSA}} = \frac{2 \pi r (r + h)}{2 \pi r h}\)
Cancel out \(2 \pi r\) from the numerator and the denominator:
\(\text{Ratio} = \frac{r + h}{h}\)
Substitute the given values \(r = 9\) cm and \(h = 25\) cm:
\(\text{Ratio} = \frac{9 + 25}{25} = \frac{34}{25}\)
This confirms the ratio is \(34 : 25\).
| Parameter | Value |
|---|---|
| Radius (r) | 9 cm |
| Height (h) | 25 cm |
| Curved Surface Area (CSA) | \(450 \pi\) sq cm |
| Total Surface Area (TSA) | \(612 \pi\) sq cm |
| Ratio (TSA : CSA) | \(612 \pi : 450 \pi\) or \(34 : 25\) |
The ratio of the total surface area to the curved surface area of the solid cylinder with radius 9 cm and height 25 cm is \(34 : 25\).
| Area Type | Formula | Notes |
|---|---|---|
| Curved Surface Area (CSA) | \(2 \pi r h\) | Area of the side surface |
| Area of one base | \(\pi r^2\) | Area of a single circular base |
| Total Surface Area (TSA) - Solid Cylinder | \(2 \pi r h + 2 \pi r^2\) or \(2 \pi r (h + r)\) | CSA + Area of two bases |
| Total Surface Area (TSA) - Hollow Cylinder (Open at both ends) | \(2 \pi r h\) | Same as CSA |
| Total Surface Area (TSA) - Hollow Cylinder (Open at one end) | \(2 \pi r h + \pi r^2\) | CSA + Area of one base |
| Volume | \(\pi r^2 h\) | Area of base × height |
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