Hydrogeological setup of a hypothetical alluvial area (where contact X-Y between two sands is vertical) is given in the schematic section. Hydraulic heads are indicated as $h_1$, $h_2$ and hydraulic conductivities as $K_1$ and $K_2$. The hydraulic head at the contact (X-Y) is ___________ m. (round off to 2 decimal places).
To find the hydraulic head at the contact (X-Y) between two sands in the alluvial area, we'll use Darcy's Law and the principle of continuity. Given:
Flow across the contact must be equal due to continuity:
Flow in Sand-I: $Q_1=K_1 \cdot \left(\frac{h_1-h_x}{L_1}\right) \cdot A$
Flow in Sand-II: $Q_2=K_2 \cdot \left(\frac{h_x-h_2}{L_2}\right) \cdot A$
Setting $Q_1$ equal to $Q_2$ and simplifying (as $A$ cancels out):
$K_1 \cdot \left(\frac{h_1-h_x}{L_1}\right) = K_2 \cdot \left(\frac{h_x-h_2}{L_2}\right)$
Substituting the values:
$20 \cdot \left(\frac{50-h_x}{3000}\right) = 30 \cdot \left(\frac{h_x-30}{4000}\right)$
Simplifying further:
$20 \cdot (50-h_x) \cdot 4000 = 30 \cdot (h_x-30) \cdot 3000$
$80000 \cdot (50-h_x) = 90000 \cdot (h_x-30)$
Expanding both sides:
$4000000 - 80000h_x = 90000h_x - 2700000$
Combining like terms:
$6700000 = 170000h_x$
Solving for $h_x$:
$h_x = \frac{6700000}{170000} = 39.41m$
The hydraulic head at contact X-Y is 39.41 m, which falls within the range 39 to 39.8.