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How many cycles of $\beta$-oxidation are required for the complete oxidation of activated Oleic acid, 18 : 1 ($\Delta^{9}$)?

This question was previously asked in
CUET PG 2026 Agri-Business Management Question Paper (25-Mar-2026) (Shift 2)
The correct answer is
8 Cycles

To determine the number of beta-oxidation cycles for Oleic acid (18:1, $\Delta^{9}$), we need to consider its chain length and the position of the double bond.

Beta-Oxidation Process Overview

Beta-oxidation is a catabolic process that breaks down fatty acids into acetyl-CoA units. Each cycle involves four enzymatic steps:

  • Oxidation (producing FADH2)
  • Hydration
  • Oxidation (producing NADH)
  • Thiolysis (releasing acetyl-CoA)

Each cycle shortens the fatty acid chain by two carbons. For a saturated fatty acid with n carbons, the number of cycles is $\frac{n}{2} - 1$. For Oleic acid (18 carbons), this would suggest $ \frac{18}{2} - 1 = 9 - 1 = 8 $ cycles if it were saturated.

Handling the Double Bond in Oleic Acid

Oleic acid is an 18-carbon fatty acid with a cis double bond between carbon 9 and carbon 10 ($\Delta^{9}$).

  • Beta-oxidation proceeds from the carboxyl end.
  • The first four cycles proceed normally, shortening the 18-carbon chain to a 10-carbon chain and producing 4 acetyl-CoA molecules.
  • After 4 cycles, the remaining 10-carbon intermediate still contains the double bond originating from the $\Delta^{9}$ position. Relative to the new carboxyl end of the 10-carbon chain, this is a cis-$\Delta^{1}$ double bond.
  • The enzyme enoyl-CoA hydratase cannot act on this cis-$\Delta^{1}$ double bond.
  • The enzyme enoyl-CoA isomerase converts the cis-$\Delta^{1}$ double bond to a trans-$\Delta^{2}$ double bond.
  • Once the double bond is in the trans-$\Delta^{2}$ position, standard beta-oxidation can resume on the 10-carbon chain.

Calculating Remaining Cycles

The 10-carbon chain (after initial processing and isomerase action) requires further breakdown:

  • For the 10-carbon chain, the number of additional cycles needed is $ \frac{10}{2} - 1 = 5 - 1 = 4 $ cycles.

Total Beta-Oxidation Cycles

The total number of cycles is the sum of the initial cycles before encountering the double bond's problematic configuration and the subsequent cycles after isomerase action:

  • Initial cycles: 4
  • Cycles after isomerase action: 4
  • Total cycles = 4 + 4 = 8

Therefore, 8 cycles of beta-oxidation are required for the complete oxidation of activated Oleic acid.

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