Hemant drives a car from Delhi to Chandigarh. He took 5 hours to cover the distance of 250 km and took 7 hrs to reach back Delhi. What is the average speed of the car in this journey?
41.6 km/hr
The distance covered while going from Delhi to Chandigarh is 250 km, and the same distance of 250 km is covered again while returning to Delhi, so the total distance travelled is 250 km plus 250 km, which equals 500 km.
The time taken for the onward journey is 5 hours and the time taken for the return journey is 7 hours, so the total time taken is 5 hours plus 7 hours, which equals 12 hours.
Average speed is calculated as total distance divided by total time, so the average speed is 500 km divided by 12 hours.
Dividing 500 by 12 gives approximately 41.6 km/hr.
Hence, the average speed of the car for this journey is 41.6 km/hr.
Important Questions from Speed and Velocity
Which of the following quantities specifies its speed with direction?
The basic unit of speed of an object is ______.
- Which of the following represents non-uniform linear velocity?
- Which of the following describes the nature of the average speed?
- An object starts from rest at x = 0 m and t = 0 s. It moves with a constant acceleration of \(2 \text{ m/s}^2\) along the x-axis. What is its average velocity between time 1 s and 5 s?
