Greater the value of _______ of a material, the more rapidly it will conduct heat.
The question asks about the property of a material that determines how rapidly it conducts heat. This property is directly related to how easily heat energy flows through the material from a region of higher temperature to a region of lower temperature.
Thermal conductivity is a fundamental property of a material that quantifies its ability to conduct heat. It is often denoted by the symbol \(k\) or \(\lambda\). A material with high thermal conductivity transfers heat efficiently, while a material with low thermal conductivity acts as a thermal insulator, resisting the flow of heat.
Imagine you have a hot object and a cold object, connected by a bar made of a certain material. Thermal conductivity tells you how quickly heat will flow from the hot object, through the bar, to the cold object.
According to Fourier's Law of Heat Conduction, the rate of heat transfer (\(Q/t\)) through a material is proportional to the area (\(A\)), the temperature difference (\(\Delta T\)), and inversely proportional to the thickness (\(\Delta x\)). The constant of proportionality is the thermal conductivity (\(k\)).
\(\frac{Q}{t} = -k A \frac{\Delta T}{\Delta x}\)
The negative sign indicates that heat flows in the direction of decreasing temperature. For a given area, temperature difference, and thickness, a higher value of \(k\) means a greater rate of heat transfer (\(Q/t\)). This directly translates to heat being conducted more rapidly through the material.
Let's examine each option in the context of rapid heat conduction:
Based on these definitions, thermal conductivity is the property that directly determines the rate of heat conduction. A material with high thermal conductivity, such as copper or aluminum, will conduct heat much faster than a material with low thermal conductivity, such as foam or fiberglass, which are used as insulators.
Thus, the greater the value of thermal conductivity of a material, the more rapidly it will conduct heat.
| Property | Description | Relevance to Rapid Heat Conduction |
|---|---|---|
| Thermal Conductivity | Measures a material's ability to conduct heat. | Directly proportional to the rate of heat conduction; higher value means faster conduction. |
| Melting Point | Temperature at which a solid becomes a liquid. | Defines a transition point, not the rate of heat transfer in a given state. |
| Latent Heat | Energy involved in a phase change. | Energy for phase change, not the rate of heat transfer through a stable phase. |
| Regelation | Melting and refreezing under pressure changes (e.g., ice). | Specific phase behavior under pressure, not general conduction rate. |
The concept of thermal conductivity is crucial in many applications:
Understanding thermal conductivity helps in selecting appropriate materials for various purposes where heat transfer needs to be either maximized or minimized.
Identify the material having low coefficient of volume expansion
Identify the material having high coefficient of volume expansion.
Identify the material having the lowest coefficient of linear expansion.
Thermal expansion of solids are:
A copper rod and a steel rod are to have lengths LC and LS, such that the difference between their lengths is the same at all ambient temperatures. If the coefficients of linear expansion of copper and steels are αC and αS respectively. The lengths are related to the coefficient of linear expansion as :
How much should the temperature of a brass rod be increased so as to increase its length by 1%?
Given: for brass α = 0.00002/°CA wooden wagon wheel has an outside diameter of 3750 mm. The iron tire for this wheel is deliberately made smaller so that it can be shrunk in place to be a tight fit. If the tire's inside diameter is 3737 mm at 20°C, the temperature to which it must be heated to fit over the wheel? The coefficient of linear expansion of the steel is 1.2 × 10-5/°C.
A cylinder of cross-sectional radius 1 cm and height 4 cm is heated from 0°C to 100°C. If the coefficient of linear expansion α = 4 × 10-4/°C, what will be the increase in the volume of the cylinder?