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Question

Given below are two statements : one is labelled as Assertion (A) and the other is labelled as Reason (R).
Assertion (A) : FCC lattice has higher packing fraction than simple cubic lattice.
Reason (R) : FCC contains less atoms per unit cell than simple cubic.
In the light of the above statements, choose the most appropriate answer from the options given below :

This question was previously asked in
CUET PG 2026 Agri-Business Management Question Paper (25-Mar-2026) (Shift 2)
The correct answer is
(A) is correct but (R) is not correct

FCC vs SC Packing Fraction

This section analyzes the Assertion (A) and Reason (R) regarding the packing efficiency and atom count in Face-Centered Cubic (FCC) and Simple Cubic (SC) crystal structures.

Assertion (A): Packing Fraction

Assertion (A) states: FCC lattice has a higher packing fraction than simple cubic lattice.

  • Calculation for Simple Cubic (SC):
    • Atoms per unit cell = 1.
    • Relationship between atomic radius ($r$) and lattice constant ($a$): $a = 2r$, so $r = a/2$.
    • Packing Fraction (PFSC) = $ \frac{\text{Volume of atoms}}{\text{Volume of unit cell}} = \frac{1 \times \frac{4}{3}\pi r^3}{a^3} = \frac{\frac{4}{3}\pi (\frac{a}{2})^3}{a^3} = \frac{\pi}{6} \approx 0.5236 $
  • Calculation for Face-Centered Cubic (FCC):
    • Atoms per unit cell = 4.
    • Relationship between atomic radius ($r$) and lattice constant ($a$): The face diagonal is $4r = a\sqrt{2}$, so $r = \frac{a\sqrt{2}}{4}$.
    • Packing Fraction (PFFCC) = $ \frac{4 \times \frac{4}{3}\pi r^3}{a^3} = \frac{\frac{16}{3}\pi (\frac{a\sqrt{2}}{4})^3}{a^3} = \frac{16\pi a^3 2\sqrt{2}}{3 \times 64 a^3} = \frac{\pi\sqrt{2}}{3} \approx 0.7405 $

Comparing the packing fractions, PFFCC ($ \approx 0.7405 $) is significantly greater than PFSC ($ \approx 0.5236 $). Thus, Assertion (A) is correct.

Reason (R): Atoms Per Unit Cell

Reason (R) states: FCC contains less atoms per unit cell than simple cubic.

  • A Simple Cubic (SC) unit cell has atoms only at the 8 corners, contributing $8 \times \frac{1}{8} = 1$ atom per unit cell.
  • A Face-Centered Cubic (FCC) unit cell has atoms at the 8 corners and the centers of the 6 faces, contributing $(8 \times \frac{1}{8}) + (6 \times \frac{1}{2}) = 1 + 3 = 4$ atoms per unit cell.

Since the FCC unit cell contains 4 atoms and the SC unit cell contains 1 atom, FCC contains more atoms per unit cell, not less. Therefore, Reason (R) is incorrect.

Select Correct Option

Based on the analysis:

  • Assertion (A) is correct.
  • Reason (R) is incorrect.

This matches the condition where (A) is correct but (R) is not correct.

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