This problem involves calculating the length of a train and a platform using concepts of speed, time, and distance, including relative speed.
First, convert the given speeds from kilometers per hour (km/h) to meters per second (m/s) because the time is given in seconds. The conversion factor is $1 \, \text{km/h} = \frac{5}{18} \, \text{m/s}$.
When a train passes a man running in the same direction, the relative speed is the difference between their speeds. The distance the train covers relative to the man is its own length ($L_{\text{train}}$).
The length of the train is 175 meters.
When a train passes a platform, the total distance covered is the sum of the train's length ($L_{\text{train}}$) and the platform's length ($L_{\text{platform}}$). The train travels at its own constant speed.
The length of the platform is 200 meters.
The length of the train is 175 meters and the length of the platform is 200 meters.
In a 500 m race, P and Q have speeds in the ratio of 3: 4. Q starts the race when P has already covered 140 m.
What is the distance between P and Q (in m) when P wins the race?
A vehicle is moving at a speed of 12 m/s on a level road. It applies emergency brakes and starts to skid without rolling in a straight path. The deceleration of the vehicle is constant after braking and it comes to rest at a distance of 15 m. Assuming, $g = 10$ m/s$^2$, the coefficient of kinetic friction between the tyres and road is _________ [round off to 2 decimal places]
Two trains started at 7AM from the same point. The first train travelled north at a speed of 80km/h and the second train travelled south at a speed of 100 km/h. The time at which they were 540 km apart is _______________ AM.