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Question

Four letter clusters have been given out of which three are alike in some manner, while one is different. Choose the odd one.

This question was previously asked in
SSC GD 2018 Question Paper Hindi (09-Mar-2019) (Shift 1)
The correct answer is

JKNQ

Odd One Out: Letter Cluster Analysis

The question requires identifying the letter cluster that doesn't follow the same pattern as the others. We analyze the pattern by looking at the alphabetical positions of the letters.

Analyzing Letter Patterns

Assign numerical values to each letter (A=1, B=2, ..., Z=26). Calculate the difference between consecutive letters in each cluster.

Cluster Comparison Table

Cluster Letters Positions Difference 1-2 Difference 2-3 Difference 3-4 Pattern
1. YZBE Y, Z, B, E 25, 26, 2, 5 $26 - 25 = 1$ $2 - 26 = -24 \equiv 2 \pmod{26}$
(or $26 \rightarrow 1 \rightarrow 2$)
$5 - 2 = 3$ +1, +2, +3
2. DEGJ D, E, G, J 4, 5, 7, 10 $5 - 4 = 1$ $7 - 5 = 2$ $10 - 7 = 3$ +1, +2, +3
3. JKNQ J, K, N, Q 10, 11, 14, 17 $11 - 10 = 1$ $14 - 11 = 3$ $17 - 14 = 3$ +1, +3, +3
4. QRTW Q, R, T, W 17, 18, 20, 23 $18 - 17 = 1$ $20 - 18 = 2$ $23 - 20 = 3$ +1, +2, +3

Identifying the Different Cluster

Three clusters (YZBE, DEGJ, QRTW) follow a sequential pattern of differences between letters: +1, +2, +3.

The cluster JKNQ has the pattern +1, +3, +3, which is different from the others.

Therefore, JKNQ is the odd one out.

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