For showing the growth of population for the last 8 years, the best diagram is
simple bar diagram
When we want to show how a value changes over time, like the growth of population over several years, we need a type of diagram that can clearly display the data for each specific time point and make it easy to see the trend.
Let's look at the given options to determine the best diagram for showing the growth of population for the last 8 years.
Different types of diagrams are used for visualizing different kinds of data. For showing population growth over a specific period like 8 years, we are dealing with time-series data. Let's evaluate the options:
A simple bar diagram is well-suited for showing population growth over a specific period like the last 8 years. Each bar represents the population figure for a particular year. This visual representation allows for easy comparison of the population from one year to the next, making the trend of population growth immediately apparent.
For time-series data like population growth over discrete periods, both bar diagrams and line diagrams are commonly used. A simple bar diagram provides a direct comparison of magnitudes at each point in time, which is excellent for showing the increase (or decrease) in population year by year over the 8-year span.
Considering the options provided, the simple bar diagram is the most appropriate choice among them for effectively illustrating the growth of population over the last 8 years.
Consider the following statements:
Statement 1: Range is not a good measure of dispersion.
Statement 2: Range is highly affected by the existence of extreme values.
Which one of the following is correct in respect of the above statements?
Data can be represented in which of the following forms?
1. Textual form
2. Tabula form
3. Graphical form
Select the correct answer using the code given below.A graph of a cumulative frequency distribution is called :
The formula to determine the number of classes given by Sturge’s Rule is which one of the following ?
1) K = 1+ 3.322 (log N)
2) K= (log N) 1.322
3)K = $\frac{1+3.322} {(log N)} $
4) K = $\frac{3.322}{(log N) + 1} $
Where :
K = Number of classes
N = Total number of observations
$\log N$ = Logarithm of the total number of observations