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Question

For frequencies below the resonant frequency, a parallel LC circuit behaves as a ________ load.

The correct answer is

Inductive

Understanding Parallel LC Circuit Behavior Below Resonance

A parallel LC circuit consists of an inductor (L) and a capacitor (C) connected in parallel. This circuit exhibits specific behavior depending on the frequency of the applied signal relative to its resonant frequency.

Resonant Frequency Calculation

The resonant frequency ($f_r$) is a critical frequency for an LC circuit. For a parallel LC circuit, it is the frequency at which the inductive reactance ($X_L$) equals the capacitive reactance ($X_C$). The formula for the resonant frequency is:

$$ f_r = \frac{1}{2\pi\sqrt{LC}} $$

where:

  • $f_r$ is the resonant frequency in Hertz (Hz)
  • $L$ is the inductance in Henries (H)
  • $C$ is the capacitance in Farads (F)

Impedance Analysis

The impedance ($Z$) of a parallel LC circuit determines how it affects the flow of current. The impedance can be calculated using the formula:

$$ Z = \frac{1}{\frac{1}{Z_L} + \frac{1}{Z_C}} $$

Substituting the impedances of the inductor ($Z_L = j\omega L$) and capacitor ($Z_C = \frac{1}{j\omega C}$):

$$ Z = \frac{1}{\frac{1}{j\omega L} + j\omega C} = \frac{1}{\frac{1 + (j\omega)^2 LC}{j\omega L}} = \frac{j\omega L}{1 - \omega^2 LC} $$

Here, $\omega$ is the angular frequency ($\omega = 2\pi f$).

Behavior Below Resonant Frequency

We need to analyze the behavior when the operating frequency ($f$) is below the resonant frequency ($f_r$). This means the angular frequency $\omega$ is less than the resonant angular frequency $\omega_r = 2\pi f_r$.

Mathematically, if $\omega < \omega_r$, then $\omega^2 < \omega_r^2$. Since $\omega_r^2 = \frac{1}{LC}$, this implies:

$$ \omega^2 LC < 1 $$

Now, let's look at the impedance formula again:

$$ Z = \frac{j\omega L}{1 - \omega^2 LC} $$

When $\omega < \omega_r$, the denominator ($1 - \omega^2 LC$) is a positive value that is close to zero as $\omega$ approaches $\omega_r$ from below. The numerator ($j\omega L$) is positive imaginary.

Therefore, the impedance $Z$ becomes a large positive imaginary number. An impedance that is purely positive imaginary represents inductive reactance ($X_L$).

Conclusion

For frequencies below the resonant frequency, the parallel LC circuit presents a large inductive reactance, causing it to behave predominantly like an inductor. This means the current lags behind the voltage.

Thus, for frequencies below the resonant frequency, a parallel LC circuit behaves as an Inductive load.

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Important Questions from Electrical Resonance

  1. Consider the following statements and choose the correct answer:

    Statement 1: In an RLC series circuit, at half-power frequencies the magnitude of total reactance is equal to resistance.

    Statement 2: In an RLC parallel circuit, at half-power frequencies the magnitude total susceptance is equal to conductance.

  2. If the bandwidth of a band-pass filter increases:

  3. What will be the bandwidth of a series resonant circuit provided it has an inductive reactance of 1000 Ohm, a capacitive reactance of 1000 Ohm and a resistance of 0.1 Ohm? It is also known that the resonant frequency is \(10^6\) rad/sec

  4. The peak output of a tuned amplifier is at 6 MHz and has a quality factor of 60. The bandwidth and 3 dB frequencies shall be

  5. A series RLC circuit has a bandwidth of 300 rad/sec at a resonant frequency of 3000 rad/sec when excited by a voltage source of 100 V. The inductance of the coil is 0.1 H. The value of R and the voltage across C are, respectively

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