$(p + q) : (p - q) : pq = 7 : 1 : 60$
If $p^2 + q^2 = r^2$, then r is equal to
We are given the ratios: $(p + q) : (p - q) : pq = 7 : 1 : 60$.
From the first part of the ratio, we consider $(p + q) : (p - q) = 7 : 1$.
This implies we can set $p + q = 7k$ and $p - q = 1k$ for some non-zero constant $k$.
Next, we use the ratio $(p + q) : pq = 7 : 60$.
Substitute the expressions $p = 4k$ and $q = 3k$ into this ratio:
The ratio $(p + q) : pq$ is therefore $(7k) : (12k^2)$.
We set this equal to the given ratio $7 : 60$: $ \frac{7k}{12k^2} = \frac{7}{60} $
Since $k \neq 0$ (otherwise $p=q=0$, which doesn't fit the ratios), we can simplify the equation:
$ \frac{1}{12k} = \frac{1}{60} $Solving for $k$, we find $12k = 60$, which means $k = \frac{60}{12} = 5$.
Now that we have found $k=5$, we can determine the specific values of $p$ and $q$:
The problem states that $p^2 + q^2 = r^2$.
Substitute the calculated values of $p$ and $q$ into this equation:
To find $r$, we take the square root of both sides:
$ r = \pm \sqrt{625} $ $ r = \pm 25 $A and B started a business with investment of ₹ $60,000$ and ₹ $90,000$ respectively. After 5 months, B left the business and C joined with a capital which is ₹ 60,000 less than that of B. If at the end of the year, the share of C in the profit was ₹ 42,000, then find the total profit earned at the end of the year.