This problem requires us to find the ratio between two quantities, A and C, based on the relationships given between A, B, and C involving percentages.
We are given two conditions:
The statement "A exceeds B by 50%" means that A is equal to B plus 50% of B.
Mathematically, this can be written as:
A = B + (50% of B)
A = B + \(0.50 \times B\)
A = B \((1 + 0.50)\)
A = \(1.50B\)
The statement "B is less than C by 25%" means that B is equal to C minus 25% of C.
Mathematically, this can be written as:
B = C - (25% of C)
B = C - \(0.25 \times C\)
B = C \((1 - 0.25)\)
B = \(0.75C\)
Now, we substitute the expression for B from Step 2 into the equation for A from Step 1:
A = \(1.50B\)
Substitute \(B = 0.75C\):
A = \(1.50 \times (0.75C)\)
A = \(1.125C\)
To find the ratio A:C, we can express the relationship A = \(1.125C\) as a fraction A/C:
\(\frac{A}{C} = 1.125\)
To express this ratio using integers, we convert the decimal 1.125 into a fraction:
1.125 = \(\frac{1125}{1000}\)
Now, we simplify this fraction by dividing both the numerator and the denominator by their greatest common divisor, which is 125:
\(\frac{1125 \div 125}{1000 \div 125} = \frac{9}{8}\)
Therefore, the ratio A:C is 9:8.
The calculated ratio of A to C is 9:8.
When x is added to each of 13, 19, 16 and 23, then the numbers so obtained, in this order, are in proportion. Then, if $5x : y :: y : (8x-4)$, and $y > 0$, what is the value of y?