Finding the x-intercept
To find the x-intercept of the equation $5x + 2y = 10$, we need to determine the value of $x$ when the line crosses the x-axis. At the x-axis, the y-coordinate is always zero.
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Start with the equation:
The given linear equation is $5x + 2y = 10$.
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Set y = 0:
To find the x-intercept, substitute $y=0$ into the equation.
$5x + 2(0) = 10$
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Simplify the equation:
Multiplying 2 by 0 gives 0.
$5x + 0 = 10$
$5x = 10$
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Solve for x:
Divide both sides of the equation by 5.
$x = \frac{10}{5}$
$x = 2$
The x-intercept is the x-coordinate where the line crosses the x-axis, which is 2.
Similar Questions
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Important Questions from Coordinate Geometry
What is the reflection of the point (-1, 5) in the line x = 1?
What are the co-ordinates of the centroid of a triangle, whose vertices are A(1, -5), B(-4, 0) and C(3, -4)?
Slope of the line AB is 4/3. Co-ordinates of points A and B are (x, -5) and (2, -3) respectively. What is the value of x?
Find the co-ordinates of the centroid of a triangle whose vertices are A(1, 4), B(7, 8) and C(10, 12).
- If x² + y² - 12x + 18y + 117 = 0, then the value of x² + y² is:
