The expression $a^2 + b^2 + c^2 - 2ab + 2ac - 2bc$ is recognized as the expansion of a squared trinomial. Specifically, it matches the form $(a - b + c)^2$.
Verification: $(a - b + c)^2 = a^2 + (-b)^2 + c^2 + 2(a)(-b) + 2(a)(c) + 2(-b)(c)$
$= a^2 + b^2 + c^2 - 2ab + 2ac - 2bc$.
Therefore, the given expression is equivalent to $(a - b + c)^2$.
Substitute the provided values for $a$, $b$, and $c$ into the equivalent expression $(a - b + c)^2$:
$a = x + y$
$b = x - y$
$c = 2x - 1$
Substituting these into $(a - b + c)^2$ yields: $((x + y) - (x - y) + (2x - 1))^2$
Simplify the terms inside the parentheses:
$(x + y) - (x - y) + (2x - 1)$
Distribute the negative sign: $x + y - x + y + 2x - 1$
Combine like terms: $(x - x + 2x) + (y + y) - 1$
$= 2x + 2y - 1$
The simplified expression inside the parentheses is $2x + 2y - 1$. Squaring this result provides the final value:
$(2x + 2y - 1)^2$
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