Find the value of \(\frac{2}{3}\)tan2 60° + 3 cos2 30° − 2 sec2 30° − \(\frac{3}{4}\)cot2 60°.
1.33
The problem asks us to find the value of a given trigonometric expression involving standard angles 30° and 60°. The expression is:
\(\frac{2}{3}\)tan² 60° + 3 cos² 30° − 2 sec² 30° − \(\frac{3}{4}\)cot² 60°
To evaluate this expression, we need to know the values of the trigonometric ratios for 30° and 60°.
Here are the required standard trigonometric values:
| Ratio | 30° | 60° |
|---|---|---|
| tan | \(\frac{1}{\sqrt{3}}\) | \(\sqrt{3}\) |
| cos | \(\frac{\sqrt{3}}{2}\) | \(\frac{1}{2}\) |
| sec | \(\frac{2}{\sqrt{3}}\) | 2 |
| cot | \(\sqrt{3}\) | \(\frac{1}{\sqrt{3}}\) |
Now, let's substitute these values into the given expression.
The expression is \(\frac{2}{3}\)tan² 60° + 3 cos² 30° − 2 sec² 30° − \(\frac{3}{4}\)cot² 60°.
Substitute the values:
Substitute these squared values back into the expression:
\(\frac{2}{3}(3) + 3(\frac{3}{4}) - 2(\frac{4}{3}) - \frac{3}{4}(\frac{1}{3})\)
Now, simplify each term:
Substitute the simplified terms back into the expression:
\(2 + \frac{9}{4} - \frac{8}{3} - \frac{1}{4}\)
Group the terms with the same denominators:
\(2 + (\frac{9}{4} - \frac{1}{4}) - \frac{8}{3}\)
Calculate the terms in the parenthesis:
\(\frac{9}{4} - \frac{1}{4} = \frac{9-1}{4} = \frac{8}{4} = 2\)
Substitute this back:
\(2 + 2 - \frac{8}{3}\)
\(4 - \frac{8}{3}\)
To subtract the fraction from the whole number, find a common denominator, which is 3:
\(\frac{4 \times 3}{3} - \frac{8}{3}\)
\(\frac{12}{3} - \frac{8}{3}\)
\(\frac{12 - 8}{3}\)
\(\frac{4}{3}\)
Convert the fraction to a decimal:
\(\frac{4}{3} \approx 1.333...\)
Rounding to two decimal places, the value is approximately 1.33.
| Angle \(\theta\) | sin \(\theta\) | cos \(\theta\) | tan \(\theta\) | csc \(\theta\) | sec \(\theta\) | cot \(\theta\) |
|---|---|---|---|---|---|---|
| 0° (0 rad) | 0 | 1 | 0 | Undefined | 1 | Undefined |
| 30° (\(\frac{\pi}{6}\) rad) | \(\frac{1}{2}\) | \(\frac{\sqrt{3}}{2}\) | \(\frac{1}{\sqrt{3}}\) | 2 | \(\frac{2}{\sqrt{3}}\) | \(\sqrt{3}\) |
| 45° (\(\frac{\pi}{4}\) rad) | \(\frac{1}{\sqrt{2}}\) | \(\frac{1}{\sqrt{2}}\) | 1 | \(\sqrt{2}\) | \(\sqrt{2}\) | 1 |
| 60° (\(\frac{\pi}{3}\) rad) | \(\frac{\sqrt{3}}{2}\) | \(\frac{1}{2}\) | \(\sqrt{3}\) | \(\frac{2}{\sqrt{3}}\) | 2 | \(\frac{1}{\sqrt{3}}\) |
| 90° (\(\frac{\pi}{2}\) rad) | 1 | 0 | Undefined | 1 | Undefined | 0 |
This problem uses trigonometric ratios at standard angles. It's also important to remember the reciprocal identities that relate some trigonometric functions:
Also, the square notation like tan² \(\theta\) means \((\text{tan } \theta)^2\), cos² \(\theta\) means \((\text{cos } \theta)^2\), and so on.
Being familiar with these identities and the standard angle values is crucial for solving trigonometric expressions and equations.
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