Find the value of $(1)^{100}+(-1)^{99}$
Exponent Calculation Steps
To find the value of the expression $(1)^{100}+(-1)^{99}$, we need to evaluate each term separately.
- Evaluate $(1)^{100}$: Any positive integer power of 1 is always 1. Therefore, $(1)^{100} = 1$.
- Evaluate $(-1)^{99}$: When -1 is raised to an odd power, the result is -1. Since 99 is an odd number, $(-1)^{99} = -1$.
Final Calculation
Now, add the results of the two terms:
$ (1)^{100} + (-1)^{99} = 1 + (-1) $
$ 1 + (-1) = 1 - 1 = 0 $
Thus, the value of the expression is 0.
Important Questions from Simplification
The value of 0.18÷0.015 is:
Simplify √81 + ³√64 —————————— ³√3³ + 4² + ³√216
Simplify: 2×[4−{2−(2−3)−(2+3)}−1]−5×[−3−(3−2)]
Simplify: \((x^{\frac{m}{n}})^{m+n} \times (x^{\frac{n}{p}})^{n+p} \times (x^{p} \times x^{m})^{p-m}\)
Which of the following is correct for divisibility?
(A) A number is divisible by 6 if it is divisible by 3 or 2.
(B) A number is divisible by 5 if its unit digit is 0 or 5.
(C) A number is divisible by 3 if its unit digit is divisible by 3.
(D) A number is divisible by 4 if the number formed by its last two digits is divisible by 4.Choose the correct answer from the options given below:
