Find the value of $(1)^{100}+(-1)^{99}$
Exponent Calculation Steps
To find the value of the expression $(1)^{100}+(-1)^{99}$, we need to evaluate each term separately.
- Evaluate $(1)^{100}$: Any positive integer power of 1 is always 1. Therefore, $(1)^{100} = 1$.
- Evaluate $(-1)^{99}$: When -1 is raised to an odd power, the result is -1. Since 99 is an odd number, $(-1)^{99} = -1$.
Final Calculation
Now, add the results of the two terms:
$ (1)^{100} + (-1)^{99} = 1 + (-1) $
$ 1 + (-1) = 1 - 1 = 0 $
Thus, the value of the expression is 0.
Important Questions from Simplification
Simplify: \((x^{\frac{m}{n}})^{m+n} \times (x^{\frac{n}{p}})^{n+p} \times (x^{p} \times x^{m})^{p-m}\)
Simplify: 2×[4−{2−(2−3)−(2+3)}−1]−5×[−3−(3−2)]
Simplify √81 + ³√64 —————————— ³√3³ + 4² + ³√216
The value of 0.18÷0.015 is:
The mean of scores obtained by 50 students is found to be 79.5. Later on, it was found that the score of one student was read as 94 in place of 49 and the score of another student was read as 69 in place of 89. Find the correct mean.
