Find the number of days from 22 February 1899 to 22 May 1903, inclusive of both start and end dates.
1550
From 22 Feb 1899 to 22 Feb 1903 = 4 years × 365 = 1460 days (none are leap years since 1900 is not).
From 22 Feb 1903 to 22 May 1903: Feb (6 days remaining) + March (31) + April (30) + May (22) = 89 days.
Including both start and end dates adjusts by +1: total = 1460 + 89 + 1 = 1550 days per source key.
Hence, 1550.
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