Find the missing analogous numbers pair : 1000 : 121 :: ?
125 : 36
The question asks us to find a pair of numbers that has the same relationship as the given pair 1000 : 121.
Let's analyze the given pair 1000 : 121.
Observe that the base of the square (11) is one greater than the base of the cube (10). Thus, the pattern is $n^3 : (n+1)^2$.
For the given pair, $n=10$. We have $10^3 = 1000$ and $(10+1)^2 = 11^2 = 121$. This confirms the pattern.
Now, we apply the identified pattern $n^3 : (n+1)^2$ to the given options:
The only pair that follows the established relationship $n^3 : (n+1)^2$ is 125 : 36.
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(NOTE: Operations should be performed on the whole numbers, without breaking down the numbers into its constituent digits.)
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