Find the mean proportional between 2 and 98.
14
The question asks us to find the mean proportional between the numbers 2 and 98. Understanding what the mean proportional is key to solving this problem.
The mean proportional (also known as the geometric mean) between two numbers, say \(a\) and \(c\), is a number \(b\) such that the ratio of \(a\) to \(b\) is equal to the ratio of \(b\) to \(c\). This can be written as:
\[ \frac{a}{b} = \frac{b}{c} \]
By cross-multiplying, we get:
\[ b \times b = a \times c \]
\[ b^2 = ac \]
To find \(b\), we take the square root of both sides:
\[ b = \sqrt{ac} \]
So, the mean proportional between two numbers is the square root of their product.
Using the formula \(b = \sqrt{ac}\), where \(a = 2\) and \(c = 98\), we can calculate the mean proportional.
The given numbers are 2 and 98.
Multiply the two numbers together:
\[ ac = 2 \times 98 \]
\[ ac = 196 \]
Take the square root of the product (196) to find the mean proportional (\(b\)):
\[ b = \sqrt{196} \]
\[ b = 14 \]
Therefore, the mean proportional between 2 and 98 is 14.
| Concept | Value |
|---|---|
| First Number (\(a\)) | 2 |
| Second Number (\(c\)) | 98 |
| Product (\(ac\)) | 196 |
| Mean Proportional (\(\sqrt{ac}\)) | 14 |
| Type | Definition | Formula (between a and c) |
|---|---|---|
| Mean Proportional (b) | If a, b, c are in continuous proportion (a:b = b:c) | \[ b = \sqrt{ac} \] |
| Third Proportional (c) | If a, b, c are in continuous proportion (a:b = b:c), c is the third proportional to a and b | \[ c = \frac{b^2}{a} \] |
| Fourth Proportional (d) | If a, b, c, d are in proportion (a:b = c:d), d is the fourth proportional to a, b, and c | \[ d = \frac{bc}{a} \] |
A proportion is a statement that two ratios are equal. For example, \(a:b = c:d\).
Understanding the relationship between ratio, proportion, and different types of proportionals like mean, third, and fourth proportional is essential for solving problems in this area of mathematics.
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