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Question

Fill in the blank with the most appropriate option.

The Universal Constant of Gravitation is ________.

This question was previously asked in
RRB ALP 2018 CBT 2 Fitter Question Paper (21-Jan-2019) (Shift 3)
The correct answer is

6.67 × 10-11 Nm2/kg2

Understanding the Universal Constant of Gravitation

The question asks to identify the value of the Universal Constant of Gravitation. This constant is a fundamental physical constant used in Newton's Law of Universal Gravitation.

Newton's Law of Universal Gravitation states that every particle attracts every other particle in the universe with a force which is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers. Mathematically, this force ($F$) between two objects with masses $m_1$ and $m_2$ separated by a distance $r$ is given by the formula:

$$F = G \frac{m_1 m_2}{r^2}$$

In this formula, $G$ is the Universal Constant of Gravitation. It is called 'universal' because its value is believed to be the same throughout the entire universe, regardless of the nature of the masses or the medium between them.

Value and Units of the Universal Gravitation Constant

The value of the Universal Constant of Gravitation ($G$) has been determined experimentally. The accepted value is approximately:

$$G \approx 6.67 \times 10^{-11} \text{ Nm}^2/\text{kg}^2$$

Let's look at the units. From the formula $F = G \frac{m_1 m_2}{r^2}$, we can rearrange to find the units of $G$:

$$G = \frac{F r^2}{m_1 m_2}$$

The units are: (Units of Force) × (Units of Distance)$^2$ / (Units of Mass)$^2$.

In SI units:

  • Force is measured in Newtons (N).
  • Distance is measured in meters (m).
  • Mass is measured in kilograms (kg).

So, the units of $G$ are $\text{N} \cdot \text{m}^2 / \text{kg}^2$, which is written as $\text{Nm}^2/\text{kg}^2$. This matches the units given in the options.

Analyzing the Options

Now let's compare the given options with the known value of the Universal Constant of Gravitation:

  • Option 1: $9.8 \text{ Nm}^2/\text{kg}^2$. This value is close to the acceleration due to gravity on Earth ($g \approx 9.8 \text{ m/s}^2$), not the Universal Constant of Gravitation ($G$). Also, the units are incorrect for $G$.
  • Option 2: $6.76 \times 10^{-10} \text{ Nm}^2/\text{kg}^2$. This value is close to the magnitude but the exponent is $-10$, not $-11$.
  • Option 3: $6.67 \times 10^{-11} \text{ Nm}^2/\text{kg}^2$. This matches the commonly accepted value and units for the Universal Constant of Gravitation.
  • Option 4: $6.67 \times 10^{10} \text{ Nm}^2/\text{kg}^2$. This value has a positive exponent of $10$, making it a very large number, vastly different from the actual very small value of $G$.

Based on the comparison, Option 3 correctly represents the value and units of the Universal Constant of Gravitation.

Concept Symbol Approximate Value Units
Universal Constant of Gravitation $G$ $6.67 \times 10^{-11}$ $\text{Nm}^2/\text{kg}^2$
Acceleration due to gravity (on Earth) $g$ $9.8$ $\text{m/s}^2$

Conclusion on Universal Gravitation Constant

The Universal Constant of Gravitation, $G$, is a crucial constant in physics that quantifies the strength of the gravitational force between masses. Its experimentally determined value is approximately $6.67 \times 10^{-11} \text{ Nm}^2/\text{kg}^2$. Among the given options, only option 3 provides this correct value and the appropriate units.

Revision Table: Universal Constant of Gravitation Key Facts

Property Description
Symbol $G$
Law Involved Newton's Law of Universal Gravitation
Approximate Value $6.67 \times 10^{-11}$
Units (SI) $\text{Nm}^2/\text{kg}^2$
Nature Universal constant (same everywhere)
Significance Determines the strength of gravitational force

Additional Information on Universal Gravitation Constant

While $g$ (acceleration due to gravity) varies depending on location (height, latitude, mass of the celestial body), the Universal Constant of Gravitation, $G$, is a fundamental constant of nature that is expected to be the same throughout the universe. The value of $G$ is incredibly small, which explains why gravitational force is significant only when at least one of the interacting masses is very large (like a planet or star). Measuring $G$ accurately is quite challenging due to the weakness of the gravitational force between laboratory-sized objects. Early measurements were done by scientists like Henry Cavendish.

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Similar Questions

  1. The acceleration due to gravity on the Moon is (1/6) of that on the Earth. Hence, an object weighing 12 N on the Earth will weigh ________ on the Moon.

  2. Which of the following statements is/are INCORRECT?

    A. The ratio of the force of gravitation between two masses, m1 and m2, kept at a distance R on the earth and on the moon is 1:1.
    B. Nm2/kg2 is the SI unit of G.
    C. The value of G depends on the distance between the bodies.
    D. The value of G depends on the masses of the bodies.
  3. Calculate the work done by the force of gravity when a satellite moves in an orbit of radius 40,000 km around the earth.

  4. What is the value of acceleration due to gravity on the surface of the earth?

  5. A body has a weight W on the surface of Earth. What is its weight on a planet whose mass is 15 times that of Earth and a radius that is 4 times that of the earth?

  6. The value of g on the moon is 1/6 th of the value of g on the earth. If a man can jump 1.5 m high on the earth, on the moon, he can jump up to a height of:

  7. Consider a hypothetical planet whose mass and radius are both half that of Earth. If g is the acceleration due to gravity on the surface of Earth, the acceleration due to gravity on the planet will be:

  8. A 5 kg object is raised through a height of 4 m. The Work done by the force of gravity acting on the object is (take g = 10 m/s 2):

  9. Consider a planet whose mass and radius are both twice the mass and radius of Earth. The acceleration due to gravity on the surface of the planet is n times that on Earth. The value of n is:


Important Questions from Gravity

  1. Which of the following law states that, "The force between two objects is directly proportional to the product of their masses?"

  2. Which of the following statements about the movement of planets is true?

    A. A planet's orbit is elliptical with the Sun at one of two focal points.

    B. The orbit of a planet is circular with the sun in the center.

    C. The orbit of a planet is elliptical with another planet in one of the two center-points.

    D. The orbit of a planet is circular with another planet in the center.

  3. If the mass of a person is 60 kg on the surface of earth then the same person’s mass on the surface of the moon will be:

  4. The centripetal force required to keep the moon in its orbit is provided by which force?

  5. How is the acceleration due to gravity denoted?

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