f : R – {–2} →R defined by f (x) = \(\frac{x + 1}{x + 2}\), ∀ ∈ R – {–2} is an example of-
Rational Function
The given function is defined as \(f(x) = \frac{x + 1}{x + 2}\) for all \(x \in R - \{-2\}\). The domain of the function is all real numbers except \(-2\), and the codomain is the set of real numbers \(R\).
Let's examine the structure of the function \(f(x)\). The numerator, \(x + 1\), is a polynomial of degree 1. The denominator, \(x + 2\), is also a polynomial of degree 1.
Now let's consider the definitions of the types of functions provided in the options:
Comparing the given function \(f(x) = \frac{x + 1}{x + 2}\) with these definitions, we see that it is a ratio of two polynomials, \(P(x) = x+1\) and \(Q(x) = x+2\). The denominator \(Q(x) = x+2\) is not the zero polynomial, and the domain correctly excludes the value \(x = -2\) where the denominator would be zero.
Therefore, the function \(f(x) = \frac{x + 1}{x + 2}\) is an example of a Rational Function.
The other options are not applicable:
Based on the structure and definition, the given function is a rational function.
Set P has 4 elements and set Q has 5 elements. How many numbers of injections are defined from P to Q?
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A function f(x) is defined in the following way:
f(x) = -x, x ≤ 0
= x, 0 < x < 1
= 2 - x, x ≥ 1
In this case, the function f(x) is:
Take the function f: R→ {0,1} such that \(\mathrm{F}(\mathrm{x})=\left\{\begin{array}{c} 1, \text {if x rational number } \\ 0, \text { irrational number } \end{array}\right.\)Which of the following is true?
If f : A → B and g : B → C are one–one, then gof : A → C is-