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Question

f : R – {–2} →R defined by f (x) = \(\frac{x + 1}{x + 2}\), ∀ ∈ R – {2} is an example of-

The correct answer is

Rational Function

Identifying the Type of Function \(f(x) = \frac{x + 1}{x + 2}\)

The given function is defined as \(f(x) = \frac{x + 1}{x + 2}\) for all \(x \in R - \{-2\}\). The domain of the function is all real numbers except \(-2\), and the codomain is the set of real numbers \(R\).

Let's examine the structure of the function \(f(x)\). The numerator, \(x + 1\), is a polynomial of degree 1. The denominator, \(x + 2\), is also a polynomial of degree 1.

Now let's consider the definitions of the types of functions provided in the options:

  • Rational Function: A function that can be expressed as the ratio of two polynomials, \(P(x)\) and \(Q(x)\), i.e., \(f(x) = \frac{P(x)}{Q(x)}\), where \(Q(x)\) is not the zero polynomial. The domain of a rational function is typically all real numbers \(x\) such that \(Q(x) \neq 0\).
  • Modulus Function: A function of the form \(f(x) = |x|\), which gives the absolute value of \(x\).
  • Polynomial Function: A function that can be expressed in the form \(a_n x^n + a_{n-1} x^{n-1} + \dots + a_1 x + a_0\), where \(a_i\) are constants and \(n\) is a non-negative integer.
  • Signum Function: A function defined as \(sgn(x) = 1\) if \(x > 0\), \(sgn(x) = -1\) if \(x < 0\), and \(sgn(x) = 0\) if \(x = 0\).

Comparing the given function \(f(x) = \frac{x + 1}{x + 2}\) with these definitions, we see that it is a ratio of two polynomials, \(P(x) = x+1\) and \(Q(x) = x+2\). The denominator \(Q(x) = x+2\) is not the zero polynomial, and the domain correctly excludes the value \(x = -2\) where the denominator would be zero.

Therefore, the function \(f(x) = \frac{x + 1}{x + 2}\) is an example of a Rational Function.

The other options are not applicable:

  • It is not a Modulus Function as it does not involve the absolute value of \(x\).
  • It is not a Polynomial Function because it is a ratio of polynomials, not a simple sum of terms with non-negative integer powers of \(x\).
  • It is not a Signum Function as its output is not restricted to 1, -1, or 0.

Based on the structure and definition, the given function is a rational function.

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Important Questions from Relations

  1. Set P has 4 elements and set Q has 5 elements. How many numbers of injections are defined from P to Q?

  2. What is the scope of the definition of exponential function?

  3. A function f(x) is defined in the following way:

    f(x) = -x, x ≤ 0

    = x, 0 < x < 1

    = 2 - x, x ≥ 1

    In this case, the function f(x) is:

  4. Take the function f: R→ {0,1} such that \(\mathrm{F}(\mathrm{x})=\left\{\begin{array}{c} 1, \text {if x rational number } \\ 0, \text { irrational number } \end{array}\right.\)Which of the following is true?

  5. If f : A → B and g : B C are one–one, then gof : A → C is-

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