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Question

The greatest integer function f : R → R given by f(x) = [x], (where [x] denotes the greatest integer), is _______ 

The correct answer is Neither One-One nor onto

Understanding the Greatest Integer Function f(x) = [x]

The greatest integer function, denoted by f(x) = [x], maps a real number x to the greatest integer less than or equal to x. For example:

  • [3.7] = 3
  • [5] = 5
  • [-2.3] = -3
  • [0.9] = 0

The domain of this function is R (all real numbers) and the codomain is also given as R (all real numbers).

Analyzing if f(x) = [x] is One-One

A function f: A → B is said to be One-One (or injective) if distinct elements in the domain A have distinct images in the codomain B. In other words, if $f(x_1) = f(x_2)$, then it must imply $x_1 = x_2$ for all $x_1, x_2$ in the domain.

Let's consider the greatest integer function f(x) = [x].

  • Take $x_1 = 1.5$. Then $f(x_1) = [1.5] = 1$.
  • Take $x_2 = 1.9$. Then $f(x_2) = [1.9] = 1$.

Here, we have $f(1.5) = f(1.9) = 1$, but $1.5 \neq 1.9$. Since two different elements in the domain (1.5 and 1.9) have the same image (1) in the codomain, the function f(x) = [x] is not One-One.

Analyzing if f(x) = [x] is Onto

A function f: A → B is said to be Onto (or surjective) if for every element y in the codomain B, there exists at least one element x in the domain A such that f(x) = y. This means the range of the function must be equal to its codomain.

The range of the greatest integer function f(x) = [x] consists of all the possible values that f(x) can take. As we saw from the definition, the output of the greatest integer function is always an integer.

  • For any integer k, if we take x such that $k \le x < k+1$, then $[x] = k$. This shows that every integer is in the range.

So, the range of f(x) = [x] is the set of all integers, denoted by Z.

The codomain of the function is given as R (all real numbers).

Since the range (Z) is a subset of the codomain (R), and Z is not equal to R (for example, real numbers like 0.5, π, $\sqrt{2}$ are in R but not in Z, so they are not in the range of f(x) = [x]), there are elements in the codomain that do not have a pre-image in the domain. Therefore, the function f(x) = [x] is not Onto.

Conclusion about f(x) = [x]

Based on the analysis:

  • The function f(x) = [x] is not One-One because different real numbers can map to the same integer value.
  • The function f(x) = [x] is not Onto because its range is the set of integers (Z), which is a proper subset of the codomain (R).

Therefore, the greatest integer function f : R → R given by f(x) = [x] is neither One-One nor onto.

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Important Questions from Relations

  1. Set P has 4 elements and set Q has 5 elements. How many numbers of injections are defined from P to Q?

  2. What is the scope of the definition of exponential function?

  3. A function f(x) is defined in the following way:

    f(x) = -x, x ≤ 0

    = x, 0 < x < 1

    = 2 - x, x ≥ 1

    In this case, the function f(x) is:

  4. Take the function f: R→ {0,1} such that \(\mathrm{F}(\mathrm{x})=\left\{\begin{array}{c} 1, \text {if x rational number } \\ 0, \text { irrational number } \end{array}\right.\)Which of the following is true?

  5. If f : A → B and g : B C are one–one, then gof : A → C is-

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