The greatest integer function f : R → R given by f(x) = [x], (where [x] denotes the greatest integer), is _______
The greatest integer function, denoted by f(x) = [x], maps a real number x to the greatest integer less than or equal to x. For example:
The domain of this function is R (all real numbers) and the codomain is also given as R (all real numbers).
A function f: A → B is said to be One-One (or injective) if distinct elements in the domain A have distinct images in the codomain B. In other words, if $f(x_1) = f(x_2)$, then it must imply $x_1 = x_2$ for all $x_1, x_2$ in the domain.
Let's consider the greatest integer function f(x) = [x].
Here, we have $f(1.5) = f(1.9) = 1$, but $1.5 \neq 1.9$. Since two different elements in the domain (1.5 and 1.9) have the same image (1) in the codomain, the function f(x) = [x] is not One-One.
A function f: A → B is said to be Onto (or surjective) if for every element y in the codomain B, there exists at least one element x in the domain A such that f(x) = y. This means the range of the function must be equal to its codomain.
The range of the greatest integer function f(x) = [x] consists of all the possible values that f(x) can take. As we saw from the definition, the output of the greatest integer function is always an integer.
So, the range of f(x) = [x] is the set of all integers, denoted by Z.
The codomain of the function is given as R (all real numbers).
Since the range (Z) is a subset of the codomain (R), and Z is not equal to R (for example, real numbers like 0.5, π, $\sqrt{2}$ are in R but not in Z, so they are not in the range of f(x) = [x]), there are elements in the codomain that do not have a pre-image in the domain. Therefore, the function f(x) = [x] is not Onto.
Based on the analysis:
Therefore, the greatest integer function f : R → R given by f(x) = [x] is neither One-One nor onto.
Set P has 4 elements and set Q has 5 elements. How many numbers of injections are defined from P to Q?
What is the scope of the definition of exponential function?
A function f(x) is defined in the following way:
f(x) = -x, x ≤ 0
= x, 0 < x < 1
= 2 - x, x ≥ 1
In this case, the function f(x) is:
Take the function f: R→ {0,1} such that \(\mathrm{F}(\mathrm{x})=\left\{\begin{array}{c} 1, \text {if x rational number } \\ 0, \text { irrational number } \end{array}\right.\)Which of the following is true?
If f : A → B and g : B → C are one–one, then gof : A → C is-