Dinesh starts from Point A and drives 20 km towards West. He then takes a left turn, drives 18 km, turns left and drives 21 km. He then takes a left turn and drives 28 km. He takes a final left turn, drives 1 km and stops at Point P. How far (shortest distance) and towards which direction should he drive in order to reach Point A again? (All turns are 90° turns only unless specified.)
10 km to the South
Take East as +x and North as +y, and start at A = (0, 0).
Drive 20 km West: facing West, move to (−20, 0).
Left turn from West faces South; drive 18 km: (−20, −18).
Left turn from South faces East; drive 21 km: (−20+21, −18) = (1, −18).
Left turn from East faces North; drive 28 km: (1, −18+28) = (1, 10).
Left turn from North faces West; drive 1 km: (1−1, 10) = (0, 10) = Point P.
Point A is at (0, 0) and P is at (0, 10). The x-coordinates match, so A is due South of P at a distance of 10 km.
Hence, Dinesh must drive 10 km to the South.
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