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Question

Consider a firm in a Duopoly market with product differentiation in which, Duopolist I faces a demand function given by:
\(p_1 = 200 - 4q_1 - 2q_2\)

The cost function of Duopolist I is:
\(c_1 = 5q_1^2\)

Assume that Duopolist II has  \(\frac{1}{3}\)rd share of the whole market.
Find out optimal price, output and profit for Duopolist I. Also find out the output of Duopolist II.

This question was previously asked in
UPSC CSE 2025 (Prelims) CSAT Official Paper (25-May-2025)

Step 1: Relationship between \(q_1\) and \(q_2\)

The problem specifies that Duopolist II has a \(\frac{1}{3}\) share of the market. This implies the total quantity produced in the market is shared between both firms in the ratio of 2:1, with Duopolist I producing more than Duopolist II.

Let the total quantity produced in the market be \(q_1 + q_2\), where:

  • \(q_1\) is the quantity produced by Duopolist I.
  • \(q_2\) is the quantity produced by Duopolist II.

Given that Duopolist II has a \(\frac{1}{3}\) share of the market, the remaining \(\frac{2}{3}\) of the market is produced by Duopolist I. Therefore, we can express the relationship between \(q_1\) and \(q_2\) as:

\(q_2 = \frac{1}{3} (q_1 + q_2)\)

Multiplying both sides by 3:

\(3q_2 = q_1 + q_2\)

Now, moving the terms involving \(q_2\) to one side:

\(2q_2 = q_1\)

This gives us the relationship between the output of Duopolist I and Duopolist II:

\(q_2 = \frac{q_1}{2}\)

Thus, Duopolist II’s output is half of Duopolist I’s output.

Step 2: Deriving Duopolist I’s Profit Function

Duopolist I’s profit \(\pi_1\) is given by the difference between its total revenue and its total cost. The revenue for Duopolist I is given by:

Revenue = \(p_1 \cdot q_1\)

Substitute the demand function \(p_1 = 200 - 4q_1 - 2q_2\) into the revenue equation:

Revenue = \((200 - 4q_1 - 2q_2) \cdot q_1\)

Now, substitute \(q_2 = \frac{q_1}{2}\):

Revenue = \((200 - 4q_1 - q_1) \cdot q_1 = (200 - 5q_1) \cdot q_1 = 200q_1 - 5q_1^2\)

The cost function for Duopolist I is given by:

\(C_1 = 5q_1^2\)

Thus, Duopolist I’s profit is:

\(\pi_1 = \text{Revenue} - C_1 = (200q_1 - 5q_1^2) - 5q_1^2 = 200q_1 - 10q_1^2\)

Step 3: Maximizing Profit

To find the optimal output for Duopolist I \(q_1^*\), we take the derivative of the profit function with respect to \(q_1\) and set it equal to zero:

\(\frac{d\pi_1}{dq_1} = 200 - 20q_1 = 0\)

Solving for \(q_1\):

\(20q_1 = 200 \quad \Rightarrow \quad q_1^* = \frac{200}{20} = 10\)

Thus, the optimal output for Duopolist I is \(q_1^* = 10\).

Step 4: Finding the Output of Duopolist II

From the relationship \(q_2 = \frac{q_1}{2}\), we can find Duopolist II’s output:

\(q_2^* = \frac{q_1^*}{2} = \frac{10}{2} = 5\)

Thus, the optimal output for Duopolist II is \(q_2^* = 5\).

Step 5: Determining the Price for Duopolist I

Substitute \(q_1^* = 10\) and \(q_2^* = 5\) into the demand function to find the price:

\(p_1 = 200 - 4q_1 - 2q_2 p_1^* = 200 - 4(10) - 2(5) = 200 - 40 - 10 = 150\)

Thus, the optimal price for Duopolist I is \(p_1^* = 150\).

Step 6: Calculating Duopolist I’s Profit

Finally, we calculate the profit for Duopolist I by substituting the values of \(q_1 = 10\) and \(p_1 = 150\) into the profit formula:

\(\pi_1 = p_1 \cdot q_1 - C_1\) 
\(\pi_1 = 150 \cdot 10 - 5(10)^2 = 1500 - 500 = 1000\)

Thus, the profit for Duopolist I is (\(\pi_1^* = 1000\)).

Conclusion:

Optimal Output of Duopolist I (\(q_1^*\)): 10 units

Optimal Output of Duopolist II (\(q_2^*\)): 5 units

Optimal Price for Duopolist I (\(p_1^*\)): 150

Profit of Duopolist I (\(\pi_1^*\)): 1000

In this scenario, Duopolist I produces 10 units and charges a price of 150, yielding a profit of 1000. Duopolist II, with a market share of (\(\frac{1}{3}\)), produces 5 units.

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