In memory management, page size is always, power of 2.
In operating systems, memory management techniques are crucial for efficiently allocating and utilizing system memory. One common technique is paging, where memory is divided into fixed-size blocks called pages (in main memory) and frames (in secondary storage). The page size plays a significant role in how memory is managed.
When a program runs, it uses logical addresses. The system's Memory Management Unit (MMU) needs to translate these logical addresses into physical memory addresses. A logical address is typically divided into two parts:
The formula for a logical address can be represented as:
Logical Address = (Page Number × Page Size) + Page Offset
Alternatively, thinking in terms of bits, if the total logical address space has m bits and the page size is $2^k$, then:
The question states that the page size is always a power of 2. This is a design choice made primarily because it greatly simplifies the process of address translation. Here's why:
Therefore, the main reason for choosing a page size that is a power of 2 is:
Let's look at why the other options are not the primary reason:
Choosing a page size that is a power of 2 is a fundamental aspect of paging in memory management because it allows for very fast and simple hardware-based translation of logical addresses into their corresponding page number and page offset components.
| List I | List II |
| A. Clustered Page Table | I. Generally considered inappropriate for 64 bit architectures. |
| B. Hierarchical Page Table | II. Has only entry for each real page (or frame) of memory. |
| C. Segmentation | III. Useful for Sparse address spaces. |
| D. Inverted Page Table | IV. Supports a user view of the system. |
Which of the following is a type of memory and is similar to RAM?
200 μs should be the memory size of a digital storage oscilloscope to be able to record a transient of 10 seconds with a time resolution of 200 μs?