Note: 1K=$2^{10}$, 1M=$2^{20}$, 1G=$2^{30}$
This solution calculates the total size of the Translation Lookaside Buffer (TLB) in bytes based on the provided parameters like TLB reach, page size, address space sizes, and the structure of a TLB entry.
The number of entries in the TLB is determined by dividing the TLB's reach by the page size.
Each TLB entry contains several fields. We need to calculate the total bits required for one entry.
The total size of the TLB is the number of entries multiplied by the size of each entry.
Therefore, the size of the TLB is 1536 bytes.
| List I | List II |
| A. Clustered Page Table | I. Generally considered inappropriate for 64 bit architectures. |
| B. Hierarchical Page Table | II. Has only entry for each real page (or frame) of memory. |
| C. Segmentation | III. Useful for Sparse address spaces. |
| D. Inverted Page Table | IV. Supports a user view of the system. |
Which of the following is a type of memory and is similar to RAM?
200 μs should be the memory size of a digital storage oscilloscope to be able to record a transient of 10 seconds with a time resolution of 200 μs?