Question
_____ °Celsius = 167 Fahrenheit
This question was previously asked in
RRB ALP/Technician 2018 CBT 2 Electronics Mechanic Question Paper (23-Jan-2019) (Shift 1)
The correct answer is
75
Step 1:
\(C=\frac59(F-32)=\frac59(167-32)=75^\circ C\)
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