All Exams Test series for 1 year @ ₹349 only
Question

At a disco the beam revolves $360^\circ$ in 20 minutes. Its maximum coverage is 20 m long. After 2 minutes what length the beam would have covered from its starting point?

This question was previously asked in
RRB ALP 2018 CBT 2 Fitter Question Paper (21-Jan-2019) (Shift 3)
The correct answer is
$4\pi\text{ m}$

Disco Beam Revolution Calculation

The problem asks for the length covered by a revolving disco beam after a specific time, given its total revolution time and maximum coverage length.

Determining Angular Speed

First, find the angular speed of the beam.

  • The beam completes a full $360^\circ$ revolution in 20 minutes.
  • Angular speed ($\omega$) = Total Angle / Total Time
  • $\omega = \frac{360^\circ}{20 \text{ min}} = 18^\circ \text{ per minute}$
  • Convert the angular speed to radians per minute for arc length calculation:
  • $\omega = 18^\circ/\text{min} \times \frac{\pi \text{ radians}}{180^\circ} = \frac{\pi}{10} \text{ radians per minute}$

Calculating Angle Covered

Next, calculate the angle the beam rotates through in 2 minutes.

  • Angle ($\theta$) = Angular Speed ($\omega$) $\times$ Time ($t$)
  • $\theta = \left(\frac{\pi}{10} \text{ radians/min}\right) \times (2 \text{ min})$
  • $\theta = \frac{2\pi}{10} = \frac{\pi}{5} \text{ radians}$

Calculating Covered Length

Finally, calculate the arc length covered using the angle and the maximum coverage length (radius).

  • The maximum coverage length is given as 20 m. Assume this is the radius ($r$) of the circle traced by the beam. So, $r = 20$ m.
  • Arc Length ($L$) = Radius ($r$) $\times$ Angle in Radians ($\theta$)
  • $L = 20 \text{ m} \times \frac{\pi}{5}$
  • $L = 4\pi \text{ m}$

Therefore, after 2 minutes, the beam would have covered a length of $4\pi$ m.

Was this answer helpful?

Important Questions from Circular Measure of Angles

  1. Which of the following values of A and B satisfies, sin(A + B) = sin A + sin B, where

  2. If tan 3 θ = cot(θ - 22°), where 3 θ is an angle, find the value of θ.

  3. The value of 4cos\(\left( {\frac{\pi }{6}\, - \,\alpha } \right)\) sin\(\left( {\frac{\pi }{3}\, - \,\alpha } \right)\) is equal to:

  4. 1 + tan 15° cot 75° is equal to:

  5. If tan θ = 1/√5, find the value of cosec2θ – sec2θ.

Need Expert Advice?
Upcoming Exams
RRB Technician
October 06, 2026
RRB JE
October 27, 2026
RRB ALP
November 03, 2026
Test Series
RRB ALP img
Railways
RRB ALP 2026 Mock Test series
1035 Tests 1 Tests Free
1082 Attempts
4.3(238)
English, Hindi

Start Your Preparation with Prepp Mobile App

Download the app from Google Play & App Store
Download the app from Google Play & App Store
Prepp Mobile App