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Question

At a disco the beam revolves $360^\circ$ in 20 minutes. Its maximum coverage is 20 m long. After 2 minutes what length the beam would have covered from its starting point?

The correct answer is
$4\pi\text{ m}$

Disco Beam Revolution Calculation

The problem asks for the length covered by a revolving disco beam after a specific time, given its total revolution time and maximum coverage length.

Determining Angular Speed

First, find the angular speed of the beam.

  • The beam completes a full $360^\circ$ revolution in 20 minutes.
  • Angular speed ($\omega$) = Total Angle / Total Time
  • $\omega = \frac{360^\circ}{20 \text{ min}} = 18^\circ \text{ per minute}$
  • Convert the angular speed to radians per minute for arc length calculation:
  • $\omega = 18^\circ/\text{min} \times \frac{\pi \text{ radians}}{180^\circ} = \frac{\pi}{10} \text{ radians per minute}$

Calculating Angle Covered

Next, calculate the angle the beam rotates through in 2 minutes.

  • Angle ($\theta$) = Angular Speed ($\omega$) $\times$ Time ($t$)
  • $\theta = \left(\frac{\pi}{10} \text{ radians/min}\right) \times (2 \text{ min})$
  • $\theta = \frac{2\pi}{10} = \frac{\pi}{5} \text{ radians}$

Calculating Covered Length

Finally, calculate the arc length covered using the angle and the maximum coverage length (radius).

  • The maximum coverage length is given as 20 m. Assume this is the radius ($r$) of the circle traced by the beam. So, $r = 20$ m.
  • Arc Length ($L$) = Radius ($r$) $\times$ Angle in Radians ($\theta$)
  • $L = 20 \text{ m} \times \frac{\pi}{5}$
  • $L = 4\pi \text{ m}$

Therefore, after 2 minutes, the beam would have covered a length of $4\pi$ m.

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Important Questions from Circular Measure of Angles

  1. If sec 4θ = cosec (θ + 20°), then θ is equal to:

  2. The value of sin 260° cos 245° + 2 tan 260° - cosec 230° is equal to:

  3. Find the value of sin 4 30° + cos 4 30° - sin 25° cos 65° - sin 65° cos25°.

  4. \(\left( {\frac{{2\tan 30^\circ }}{{1 - {{\tan }^2}\;30^\circ }}} \right){\rm{}} = {\rm{}}?\)
  5. Find the value of cot 25°cot 35°cot 45°cot 55°cot 65°.

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