As the frequency increases, the impedance of the inductor _______.
increases
The question asks how the impedance of an inductor changes as the frequency increases. Let's explore the concept of inductor impedance.
In AC circuits, components like resistors, capacitors, and inductors oppose the flow of alternating current. This opposition is called impedance ($Z$). For a pure inductor, the opposition to AC current is specifically called inductive reactance ($X_L$).
The inductive reactance ($X_L$) of an inductor is given by the formula:
$$X_L = 2\pi fL$$
Where:
For a pure inductor, the impedance ($Z$) is equal to its inductive reactance ($X_L$). So, $Z = X_L$.
Looking at the formula \(X_L = 2\pi fL\), we can see how inductive reactance relates to frequency (\(f\)) and inductance (\(L\)). The term \(2\pi L\) is a constant for a given inductor. Therefore, the inductive reactance \(X_L\) is directly proportional to the frequency \(f\).
$$X_L \propto f$$
This means that if the frequency \(f\) increases, the inductive reactance \(X_L\) also increases. Since the impedance of a pure inductor is equal to its inductive reactance ($Z = X_L$), an increase in frequency leads to an increase in the impedance of the inductor.
Let's consider the options based on this understanding:
Therefore, as the frequency increases, the impedance of the inductor increases.
| Parameter | Change | Effect on Inductive Reactance (\(X_L\)) | Effect on Inductor Impedance (\(Z\)) |
|---|---|---|---|
| Frequency (\(f\)) | Increases | Increases (\(X_L \propto f\)) | Increases (\(Z = X_L\)) |
| Frequency (\(f\)) | Decreases | Decreases | Decreases |
| Quantity | Relationship with Frequency (\(f\)) | Formula |
|---|---|---|
| Inductive Reactance (\(X_L\)) | Directly Proportional | \(X_L = 2\pi fL\) |
| Inductor Impedance (\(Z\)) | Directly Proportional | \(Z = X_L = 2\pi fL\) |
Impedance is a general concept for AC circuits. Different components behave differently with frequency:
$$X_C = \frac{1}{2\pi fC}$$
Where \(C\) is the capacitance. For a capacitor, the capacitive reactance \(X_C\) is inversely proportional to the frequency \(f\).$$X_C \propto \frac{1}{f}$$
This means as frequency increases, the impedance of a capacitor decreases. \(Z_C = X_C\).In summary, inductors and capacitors have impedance that varies with frequency, while resistors typically do not.
Two bulbs of 500 W and 200 W rated at 250 V will have resistance ratio as
Which of the following value of a complex current wave is equal to the square root of the sum of the square of the RMS value of the individual components?
What is the SI unit of electric charge?
Calculate the total DC resistance of a 100 metre roll of 2.5 mm2 copper wire if the resistivity of copper at 20° C is 1.72 × 10-8 Ω metre
If three 5 μF capacitors are connected in parallel, then the net capacitance is