Building Logic Puzzle Solution
The problem requires finding the correct floor-person combination in a six-storey building based on several constraints.
Constraint Analysis
- Building floors: 1 to 6.
- People: Anuj, Bhola, Chandan, Dilip, Eswar, Faisal.
- Constraint 1: Anuj lives on an even-numbered floor (2, 4, or 6).
- Constraint 2: Bhola does not live on an odd floor (must be on an even floor: 2, 4, or 6).
- Constraint 3: Chandan lives on a higher floor than Faisal (Chandan > Faisal).
- Constraint 4: Dilip does not live on floor 2.
- Constraint 5: Eswar does not live on a floor immediately above or below Bhola (Eswar floor ≠ Bhola floor ± 1).
- Constraint 6: Faisal lives three floors above Dilip (Faisal floor = Dilip floor + 3).
Deduction from Key Constraints
- Faisal and Dilip's Floors: From Constraint 6 (Faisal = Dilip + 3) and Constraint 4 (Dilip ≠ 2), we can determine possible pairs for (Dilip, Faisal):
- If Dilip = 1, Faisal = 1 + 3 = 4. (Valid)
- If Dilip = 3, Faisal = 3 + 3 = 6. (Valid)
- Dilip cannot be 4 or higher, as Faisal would exceed floor 6.
This leaves two main scenarios: (Dilip=1, Faisal=4) or (Dilip=3, Faisal=6).
- Anuj and Bhola's Floors: Both Anuj and Bhola must live on even floors (2, 4, 6) from Constraints 1 and 2.
Scenario Evaluation
Scenario 1: Dilip = 3, Faisal = 6
- Floors occupied: 3 (Dilip), 6 (Faisal).
- Remaining floors: 1, 2, 4, 5.
- People remaining: Anuj, Bhola, Chandan, Eswar.
- Anuj and Bhola must occupy two of the remaining even floors {2, 4}.
- Floors 1 and 5 remain for Chandan and Eswar.
- Constraint 3 (Chandan > Faisal): Chandan > 6. This is impossible as the building only has 6 floors.
- Therefore, this scenario is invalid.
Scenario 2: Dilip = 1, Faisal = 4
- Floors occupied: 1 (Dilip), 4 (Faisal).
- Remaining floors: 2, 3, 5, 6.
- People remaining: Anuj, Bhola, Chandan, Eswar.
- Anuj and Bhola must occupy two of the remaining even floors {2, 6} (since floor 4 is taken by Faisal).
- Floors 3 and 5 remain for Chandan and Eswar.
- Constraint 3 (Chandan > Faisal): Chandan > 4. Chandan must be on floor 5 (since 6 is potentially Bhola/Anuj and 3 is too low). So, Chandan = 5.
- This leaves floor 3 for Eswar. So, Eswar = 3.
- Now we have two sub-cases for Anuj and Bhola on floors 2 and 6:
- Sub-case 2a: Anuj = 2, Bhola = 6.
- Combination: A(2), B(6), C(5), D(1), E(3), F(4).
- Check Constraint 5 (Eswar ≠ Bhola ± 1): Eswar is 3, Bhola is 6. 3 ≠ 6 ± 1 (i.e., 3 ≠ 5 or 7). This is valid.
- This yields the combination: Anuj-2, Bhola-6, Chandan-5, Dilip-1, Eswar-3, Faisal-4.
- Sub-case 2b: Anuj = 6, Bhola = 2.
- Combination: A(6), B(2), C(5), D(1), E(3), F(4).
- Check Constraint 5 (Eswar ≠ Bhola ± 1): Eswar is 3, Bhola is 2. 3 ≠ 2 ± 1 (i.e., 3 ≠ 1 or 3). This means Eswar cannot be on floor 3. This contradicts our finding that Eswar must be on floor 3 (since C=5). Therefore, this sub-case is invalid.
- Only Sub-case 2a is valid.
Final Floor-Person Combination
The derived valid combination is:
| Person |
Floor |
| Anuj |
2 |
| Bhola |
6 |
| Chandan |
5 |
| Dilip |
1 |
| Eswar |
3 |
| Faisal |
4 |
This corresponds to the sequence (Anuj, Bhola, Chandan, Dilip, Eswar, Faisal) = (2, 6, 5, 1, 3, 4).
Conclusion
Comparing this result with the given options, Option (B) matches the derived correct combination.