This problem requires us to determine the original purchase price of a smartphone by reversing a series of transactions, each involving a specific profit percentage.
The core concept here is profit calculation. Profit is the amount earned over the cost price (CP). When a profit percentage (P%) is applied, the selling price (SP) is calculated as:
$$ SP = CP \times \left(1 + \frac{P}{100}\right) $$
To find the original cost price when the selling price and profit percentage are known, we need to rearrange this formula:
$$ CP = \frac{SP}{\left(1 + \frac{P}{100}\right)} $$
We will use this inverse formula repeatedly to work backward from the final sale price to find the initial cost price.
Let's denote the cost prices for Sujata, Anita, and Sameer as $CP_{Sujata}$, $CP_{Anita}$, and $CP_{Sameer}$ respectively. The final selling price, which is the price Ansh paid Sameer, is Rs. 45,540.
Ansh bought the smartphone from Sameer for Rs. 45,540. This was Sameer's selling price ($SP_{Sameer}$), and it included a 10% profit for Sameer.
To find the price Sameer paid (his cost price, $CP_{Sameer}$), we apply the rearranged formula:
$$ CP_{Sameer} = \frac{SP_{Sameer}}{\left(1 + \frac{10}{100}\right)} $$
$$ CP_{Sameer} = \frac{45,540}{\left(1 + 0.10\right)} $$
$$ CP_{Sameer} = \frac{45,540}{1.10} $$
$$ CP_{Sameer} = 41,400 $$
This means Sameer purchased the phone for Rs. 41,400.
Sameer had purchased the phone from Anita. Therefore, Anita's selling price ($SP_{Anita}$) was Rs. 41,400 (Sameer's cost price). Anita had made a profit of 15% on this sale.
Now, we calculate Anita's cost price ($CP_{Anita}$):
$$ CP_{Anita} = \frac{SP_{Anita}}{\left(1 + \frac{15}{100}\right)} $$
$$ CP_{Anita} = \frac{41,400}{\left(1 + 0.15\right)} $$
$$ CP_{Anita} = \frac{41,400}{1.15} $$
$$ CP_{Anita} = 36,000 $$
Anita, therefore, bought the phone for Rs. 36,000.
Anita had bought the phone from Sujata. This implies Sujata's selling price ($SP_{Sujata}$) was Rs. 36,000 (Anita's cost price). Sujata earned a profit of 20% from this sale.
The question asks for the price Sujata had originally bought the phone for, which is Sujata's cost price ($CP_{Sujata}$).
Calculating Sujata's cost price:
$$ CP_{Sujata} = \frac{SP_{Sujata}}{\left(1 + \frac{20}{100}\right)} $$
$$ CP_{Sujata} = \frac{36,000}{\left(1 + 0.20\right)} $$
$$ CP_{Sujata} = \frac{36,000}{1.20} $$
$$ CP_{Sujata} = 30,000 $$
Thus, Sujata originally purchased the smartphone for Rs. 30,000.
The sequence of transactions and calculated prices can be visualized as follows:
| Seller | Buyer | Profit % by Seller | Selling Price (Cost Price for Buyer) |
| Sujata | Anita | 20% | Rs. 36,000 |
| Anita | Sameer | 15% | Rs. 41,400 |
| Sameer | Ansh | 10% | Rs. 45,540 |
By applying the profit calculation formula in reverse, we successfully traced the price back to Sujata's original purchase cost.
A shopkeeper marks the price of three identical articles, first, 60% above the Cost Price; second, 45% above the Cost Price and the third, 40% above the cost price. If he gives discount of 25% on first article, 20% on the second article and 15% on the third one, what is his overall profit percentage?
A dealer bought a six-seater Dining Table after getting successive discounts of 15% and 12%. Thereafter, he spent 10% on transport, etc. and finally sold it for Rs. 24,169.75, thereby earning a profit of 25%. What was the marked price of the Dining Table?