This solution explains how to calculate the Darcy flux (specific discharge) in a confined aquifer using the provided information and Darcy's Law.
Darcy's Law relates specific discharge ($q$) to the coefficient of permeability ($K$) and the hydraulic gradient ($i$):
$ q = K \cdot i $
The hydraulic gradient ($i$) is defined as the change in hydraulic head ($\Delta h$) over the length of flow ($L$):
$ i = \frac{\Delta h}{L} $
Substitute the given values for head difference and distance:
$ i = \frac{5 \text{ m}}{800 \text{ m}} = 0.00625 $
Use Darcy's Law, substituting the calculated gradient and the given permeability:
$ q = (40 \text{ m/day}) \times (0.00625) $
$ q = 0.25 \text{ m/day} $
The absolute value of Darcy flux through the aquifer is 0.25 m/day.