The problem asks for the final price of a laptop after applying two consecutive discounts to its original price.
Original Price of Laptop = ₹51,000
First Discount = 10%
Second Discount = 5%
The first discount reduces the price by 10%. The remaining price is 90% of the original price.
Price after 1st discount = Original Price \(\times\) (1 - Discount Rate)
Price after 1st discount = \(₹51,000 \times (1 - 0.10) = ₹51,000 \times 0.90 = ₹45,900\)
The second discount of 5% is applied to the price obtained after the first discount (₹45,900).
Final Price = Price after 1st discount \(\times\) (1 - Second Discount Rate)
Final Price = \(₹45,900 \times (1 - 0.05) = ₹45,900 \times 0.95 = ₹43,605\)
Alternatively, the final price can be calculated in one step:
Final Price = Original Price \(\times\) (1 - 1st Discount Rate) \(\times\) (1 - 2nd Discount Rate)
Final Price = \(₹51,000 \times (1 - 0.10) \times (1 - 0.05) = ₹51,000 \times 0.90 \times 0.95 = ₹43,605\)
The final price of the laptop after applying both successive discounts is ₹43,605.
A single discount equivalent to two successive discounts of 15% and 25% is:
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