An ammeter of 0-50 A range has an accuracy of ± 1% of full scale reading. The current measured is 10 A. The uncertainty in measured value is
± 5%
This solution explains how to calculate the uncertainty in a current measurement using an ammeter, considering its accuracy specifications.
We are given an ammeter with the following details:
The goal is to find the uncertainty in the measured value of 10 A, expressed as a percentage of the measured value itself.
The accuracy specification tells us the maximum error relative to the full scale reading. First, we calculate the absolute uncertainty:
Absolute Uncertainty = Accuracy Percentage $\times$ Full Scale Reading (FSR)
Absolute Uncertainty = $1\% \times 50 \, \text{A}$
Absolute Uncertainty = $\frac{1}{100} \times 50 \, \text{A}$
Absolute Uncertainty = $0.5 \, \text{A}$
This means the ammeter reading can be off by as much as $0.5 \, \text{A}$ from the true value.
The question asks for the uncertainty relative to the *measured value* (10 A), not the full scale reading.
Percentage Uncertainty = $ \left( \frac{\text{Absolute Uncertainty}}{\text{Measured Value}} \right) \times 100\% $
We substitute the values we have:
Percentage Uncertainty = $ \left( \frac{0.5 \, \text{A}}{10 \, \text{A}} \right) \times 100\% $
Percentage Uncertainty = $ 0.05 \times 100\% $
Percentage Uncertainty = $ 5\% $
Therefore, the uncertainty in the measured value of 10 A is $\pm 5\%$.
| Parameter | Value | Calculation/Notes |
|---|---|---|
| Ammeter Range (FSR) | 50 A | Given |
| Accuracy Specification | $\pm 1\%$ of FSR | Given |
| Absolute Uncertainty | $0.5 \, \text{A}$ | $1\% \times 50 \, \text{A}$ |
| Measured Current | 10 A | Given |
| Uncertainty (% of Measured Value) | $\pm 5\%$ | $(0.5 \, \text{A} / 10 \, \text{A}) \times 100\%$ |
A 0-200 V voltmeter has an accuracy of 0.75% of full-scale reading. If the voltage measured is 100 V, the error is
Which of the following types of errors are dynamic errors?
Suppose that resistors R1 and R2 are connected in parallel to give an equivalent resistor R. If resistors R1 and R2 have tolerance of 1% each the equivalent resistor R for resistor R1 = 300 Ω and R2 = 200 Ω will have tolerance of