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Question

A \(4 \frac 1 2\) digit DMM has the error specification as 0.2% of reading +10 counts. If a d.c. voltage of 100 V is read on its 200 V full-scale, the maximum error that can be expected in the reading is

The correct answer is

± 0.3%

DMM Accuracy Specification

This question requires calculating the accuracy of a Digital Multimeter (DMM). The DMM is identified as a \(4 \frac{1}{2}\) digit model. Its accuracy specification is given as 0.2% of reading + 10 counts. The task is to determine the maximum expected error when measuring a d.c. voltage of 100 V on the 200 V full-scale range.

DMM Error Components

The total error in a DMM's measurement comes from different sources. According to the provided specification, there are two primary error components:

  • Percentage of Reading Error: This component's value changes based on the magnitude of the voltage being measured (the reading).
  • Counts Error (Offset Error): This is a fixed value, often related to the resolution or the least significant digit (LSD) of the digital display.

Reading Error Calculation

The first part of the error specification is 0.2% of the reading. The measured voltage is 100 V.

Calculation for this component:

Error$_{reading}$ = $0.2\% \times \text{Reading}$

Error$_{reading}$ = $\frac{0.2}{100} \times 100 \, \text{V}$

Error$_{reading}$ = $0.2 \, \text{V}$

Counts Error Calculation

The second error component is stated as 10 counts. To find its value in volts, we need to know the voltage represented by one count on the given range.

The DMM is a \(4 \frac{1}{2}\) digit meter, meaning it can display up to 19999. The full-scale range (FS) is 200 V. For calculation, the full scale is considered divided into 20000 parts.

The voltage value for one count is calculated as:

Value per count = $\frac{\text{Full Scale Range}}{\text{Total Counts on Scale}}$

Value per count = $\frac{200 \, \text{V}}{20000}$

Value per count = $0.01 \, \text{V}$ (or 10 mV)

Now, calculate the error from 10 counts:

Error$_{counts}$ = $10 \times \text{Value per count}$

Error$_{counts}$ = $10 \times 0.01 \, \text{V}$

Error$_{counts}$ = $0.1 \, \text{V}$

Maximum DMM Error

The total maximum error is the sum of the absolute values of the two error components. This represents the worst-case error.

Total Error = $| \text{Error}_{reading} | + | \text{Error}_{counts} |$

Total Error = $0.2 \, \text{V} + 0.1 \, \text{V}$

Total Error = $0.3 \, \text{V}$

Error as Reading Percentage

The answer choices are percentages. We convert the total calculated error (0.3 V) into a percentage relative to the measured reading (100 V).

Percentage Error = $\frac{\text{Total Error}}{\text{Measured Reading}} \times 100\%$

Percentage Error = $\frac{0.3 \, \text{V}}{100 \, \text{V}} \times 100\%$

Percentage Error = $0.3\%$

Therefore, the maximum error that can be expected in the reading is $\pm 0.3\%$.

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Important Questions from Error Analysis

  1. Errors that occur after taking care of all gross and systematic errors are called as:
  2. An ammeter of 0-50 A range has an accuracy of ± 1% of full scale reading. The current measured is 10 A. The uncertainty in measured value is

  3. A 0-200 V voltmeter has an accuracy of 0.75% of full-scale reading. If the voltage measured is 100 V, the error is

  4. Suppose that resistors R1 and R2 are connected in parallel to give an equivalent resistor R. If resistors R1 and R2 have tolerance of 1% each the equivalent resistor R for resistor R1 = 300 Ω and R2 = 200 Ω will have tolerance of

  5. A voltage V1 is measured 100 times and its average and standard deviation are 100 V and 1.5 V respectively. A second voltage V2, which is independent of V1, is measured 200 times and its average and standard deviation are 150 V and 2 V respectively. V3 is computed as: V3 + V1 + V2. Then the standard deviation of V3 in volts is ________

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