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Question

A 0-200 V voltmeter has an accuracy of 0.75% of full-scale reading. If the voltage measured is 100 V, the error is

The correct answer is

1.5%

Understanding Voltmeter Error Calculation

This problem involves calculating the error in a voltmeter reading based on its accuracy specification. Voltmeter accuracy is often stated as a percentage of the full-scale reading, which represents the maximum possible value the instrument can measure.

Information Provided

  • Voltmeter Full-Scale Range (FSR): 0-200 V. This means the maximum value the voltmeter can display is 200 V.
  • Accuracy Specification: 0.75% of the full-scale reading.
  • Measured Voltage: 100 V.

Calculating the Absolute Error

The accuracy specification tells us the maximum possible deviation from the true value. Since it's given as a percentage of the full-scale reading, we first calculate the absolute error in volts:

Absolute Error = Accuracy Percentage $\times$ Full-Scale Reading

Using the given values:

Absolute Error = $0.75\% \times 200 \, \text{V}$

To calculate this, we convert the percentage to a decimal:

Absolute Error = $\frac{0.75}{100} \times 200 \, \text{V}$

Absolute Error = $0.0075 \times 200 \, \text{V}$

Absolute Error = $1.5 \, \text{V}$

So, the maximum possible error for this voltmeter, regardless of the actual reading, is 1.5 Volts.

Expressing Error as a Percentage of Measured Value

The options provided are percentages. Typically, when asked for the error in this format, it refers to the percentage error relative to the *actual measured value*. Let's calculate this:

Percentage Error = $\frac{\text{Absolute Error}}{\text{Measured Voltage}} \times 100\%$

Using the calculated absolute error and the measured voltage:

Percentage Error = $\frac{1.5 \, \text{V}}{100 \, \text{V}} \times 100\%$

Percentage Error = $0.015 \times 100\%$

Percentage Error = $1.5\%$

Conclusion

The calculated error, expressed as a percentage of the measured voltage (100 V), is 1.5%. This matches one of the options.

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Important Questions from Error Analysis

  1. Errors that occur after taking care of all gross and systematic errors are called as:
  2. An ammeter of 0-50 A range has an accuracy of ± 1% of full scale reading. The current measured is 10 A. The uncertainty in measured value is

  3. Suppose that resistors R1 and R2 are connected in parallel to give an equivalent resistor R. If resistors R1 and R2 have tolerance of 1% each the equivalent resistor R for resistor R1 = 300 Ω and R2 = 200 Ω will have tolerance of

  4. A \(4 \frac 1 2\) digit DMM has the error specification as 0.2% of reading +10 counts. If a d.c. voltage of 100 V is read on its 200 V full-scale, the maximum error that can be expected in the reading is

  5. A voltage V1 is measured 100 times and its average and standard deviation are 100 V and 1.5 V respectively. A second voltage V2, which is independent of V1, is measured 200 times and its average and standard deviation are 150 V and 2 V respectively. V3 is computed as: V3 + V1 + V2. Then the standard deviation of V3 in volts is ________

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