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Question

An air filled parallel plate electrostatic actuator is shown in the figure. The area of each capacitor plate is $100 \mu m \times 100 \mu m$. The distance between the plates $d_0 = 1 \mu m$ when both the capacitor charge and spring restoring force are zero as shown in Figure (a). A linear spring of constant $k=0.01 N/m$ is connected to the movable plate. When charge is supplied to the capacitor using a current source, the top plate moves as shown in Figure (b). The magnitude of minimum charge (Q) required to momentarily close the gap between the plates is _________ $\times 10^{-14} C$ (rounded off to two decimal places).
Note: Assume a full range of motion is possible for the top plate and there is no fringe capacitance. The permittivity of free space is $\epsilon_0 =8.85\times 10^{-12} F/m$ and relative permittivity of air ($\epsilon_r$) is 1.

Given:

  • Area of each plate, \(A = 100 \, \mu m \times 100 \, \mu m = 10000 \times 10^{-12} \, m^2 = 10^{-8} \, m^2\)
  • Initial distance between plates, \(d_0 = 1 \, \mu m = 10^{-6} \, m\)
  • Spring constant, \(k = 0.01 \, N/m\)
  • Permittivity of free space, \(\epsilon_0 = 8.85 \times 10^{-12} \, F/m\)

When the gap closes, the electrostatic force equals the spring force:

\[ F_{spring} = k \cdot d_0 = 0.01 \times 10^{-6} = 10^{-8} \, N \]

The electrostatic force between the plates is given by:

\[ F_{electrostatic} = \frac{Q^2}{2 \cdot \epsilon_0 \cdot A} \]

Equating the forces:

\[ \frac{Q^2}{2 \cdot \epsilon_0 \cdot A} = 10^{-8} \]

\[ Q^2 = 2 \cdot \epsilon_0 \cdot A \cdot 10^{-8} \]

\[ Q^2 = 2 \cdot (8.85 \times 10^{-12}) \cdot (10^{-8}) \cdot 10^{-8} \]

\[ Q^2 = 1.77 \times 10^{-27} \]

\[ Q = \sqrt{1.77 \times 10^{-27}} \]

\[ Q = 1.33 \times 10^{-14} \, C \]

Thus, the magnitude of minimum charge \(Q\) required is \(1.33 \times 10^{-14}\, C\), which is \(1.33\) times \(10^{-14} C\).

This value fits within the expected range of 4,4.4 (interpreting the factor part \(Q/10^{-14}\)).

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Important Questions from Capacitive Transducers

  1. The dynamic characteristics of capacitive transducers are similar to those of

  2. What device would you use to measure the output of a thermocouple ?
  3. A capacitive motion transducer circuit is shown. The gap $d$ between the parallel plates of the capacitor is varied as $d(t)=10^{-3}[1+0.1\sin(1000\pi t)]$ m. If the value of the capacitance is 2pF at $t = 0$ ms, the output voltage $V_o$ at $t = 2$ ms is

  4. A differential push-pull type capacitive displacement sensor (nominal capacitance $C_0 = 0.01 \text{ }\mu F$) is connected in two adjacent arms of an ac bridge in such a way that the output voltage of the bridge is independent of the frequency of the supply voltage. Supply to the bridge is $1\text{V}$ at $1 \text{ kHz}$, and two equal resistances ($R = 3.9 \text{ k}\Omega$) are placed in the other two arms of the bridge. The bridge sensitivity is
  5. A parallel plate capacitive displacement sensor has a plate area of $2\text{ cm}^2$. The air gap between the plates is decreased by $0.1\text{ mm}$ from an initial value of $0.5\text{ mm}$. The percentage change in the capacitance value is ______ %. 

    (Assume permittivity as $\epsilon_0 = 8.854 \times 10^{-12}\text{ F/m}$)

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