ABC is an equilateral triangle with side 24 cm and AD is the median. If G is the centroid of the triangle ABC, find the length (in cm) of GD.
4\(\sqrt3\)
Median of an equilateral triangle with side a: \(\dfrac{\sqrt3}{2}a\). With a=24: \(\dfrac{\sqrt3}{2}\times24 = 12\sqrt3\) cm.
The centroid divides the median in the ratio 2:1 from the vertex, so GD (from centroid to the base) is one-third of the median: \(\dfrac{12\sqrt3}{3} = 4\sqrt3\) cm.
Hence, the length of GD is \(4\sqrt3\) cm.
What is the circumcenter of the triangle ABC?
What is the centroid of the triangle ABC?
What is the foot of the altitude from the vertex A of the triangle ABC?
In ΔABC, D is a point on BC such that ∠ADB = 2∠DAC, ∠BAC = 70° and ∠B = 56°. What is the measure of ∠ADC?
In ΔABC, ∠A = 66° and ∠B = 50 °. If the bisectors of ∠B and ∠C meet at P, then ∠BPC – ∠PCA = ?