This solution explains the calculation of the Culturable Command Area (CCA) using the provided details about tubewell discharge and irrigation practices.
The tubewell discharges water at a rate of $25 \text{ m}^3/\text{h}$ and operates for $10$ hours daily.
The total daily discharge is:
$ \text{Daily Discharge} = 25 \frac{\text{m}^3}{\text{h}} \times 10 \text{ h} = 250 \text{ m}^3/\text{day} $
The irrigation interval is given as $20$ days. The total water supplied by the tubewell during this period is:
$ \text{Total Supply (20 days)} = 250 \frac{\text{m}^3}{\text{day}} \times 20 \text{ days} = 5000 \text{ m}^3 $
The average irrigation depth is $80 \text{ mm}$, which converts to $0.080 \text{ m}$. The intensity of irrigation is $80\%$ ($0.80$).
Let CCA represent the Culturable Command Area in hectares.
The actual area irrigated is $0.80 \times \text{CCA}$ hectares.
Convert the irrigated area to square meters:
$ \text{Irrigated Area (m}^2\text{)} = (0.80 \times \text{CCA}) \text{ ha} \times 10000 \frac{\text{m}^2}{\text{ha}} = 8000 \times \text{CCA} \text{ m}^2 $
The volume of water needed for this irrigation is:
$ \text{Volume Required} = \text{Irrigated Area (m}^2\text{)} \times \text{Irrigation Depth (m)} $
$ \text{Volume Required} = (8000 \times \text{CCA}) \text{ m}^2 \times 0.080 \text{ m} = 640 \times \text{CCA} \text{ m}^3 $
Equate the total water supplied over the 20-day interval to the volume required for irrigation:
$ \text{Total Supply (20 days)} = \text{Volume Required} $
$ 5000 \text{ m}^3 = 640 \times \text{CCA} \text{ m}^3 $
Solve for CCA:
$ \text{CCA} = \frac{5000}{640} $
$ \text{CCA} = \frac{500}{64} = \frac{125}{16} = 7.8125 \text{ hectares} $
Rounded to two decimal places, the CCA is $7.81$ hectares.
Irrigation water having SAR value of 20, is called
The ratio between the areas of a crop irrigated and the quantity of water required during its entire period of growth is known as
Alkaline soils are reclaimed by
For crops like potato and sugar-beets, the commonly adopted method of surface irrigation is
12 m 3/sec of water is diverted to a 30 hectare field for 5 hours. Soil probing after irrigation showed that 0.4 m of water had been stored in the root zone. Water application efficiency in this case would be