A trader sells rice, claiming 1 kg but actually gives x grams. He marks the price 20% above the cost price and gives a 10% discount on the marked price. If his overall profit is 25%, find x.
864
Take the cost price as \(1\) rupee per gram, so 1000 g of rice costs the trader \(1000\) rupees.
He marks up 20% and then gives 10% discount, so his selling-price factor per claimed kilogram is \(1.2 \times 0.9 = 1.08\) of the cost of 1000 g, that is \(1080\) rupees received for what he calls 1 kg.
But he actually hands over only \(x\) grams, which cost him \(x\) rupees. His true profit factor is \(\frac{1080}{x}\).
Given the overall profit is 25%, \(\frac{1080}{x} = 1.25\).
Solving, \(x = \frac{1080}{1.25} = 864\) grams.
Hence, the trader actually gives \(864\) grams.
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Important Questions from Dishonest Dealings
A merchant claims that he sells his goods at CP. But uses a weight of 900 g for the 1 kg weight. find his gain %
A shopkeeper cheats to the extent of 9% while buying and selling fruits, by using tampered weights. His total gain in percentage is:
A. 18.25
B. 18.81
C. 19.78
D. 18.5
What is the faulty weight used by a dishonest shopkeeper instead of the original weight of 1 kg to get a profit of 25%?
A dishonest financier claims to be lending money at simple interest, but he includes the interest every four months for calculating the principal. If he is charging an interest of 3%, the effective rate of interest becomes:
A dishonest shopkeeper claims to sell rice at the cost price of ₹95 per kg, but the weight he uses has 1 kg written on it, while it actually weighs 950 g. The profit he thus earns on selling rice having an actual weight of 95 kg rice is:
