A shopkeeper claims to sell rice at cost price, but uses a false weight and gains 25%. For 1 kg, how much rice does he actually give?
800 gm
Selling at cost price but gaining 25% via a false weight means the actual quantity given, x grams, satisfies \(\dfrac{1000-x}{x}\times100 = 25\).
\(1000-x = 0.25x \Rightarrow 1000 = 1.25x \Rightarrow x = 800\).
Hence, the shopkeeper actually gives 800 grams for every claimed 1 kg.
A shopkeeper cheats to the extent of $10\%$ while buying as well as while selling. While he was eventually caught and punished, at what percent was he gaining till then?
A shopkeeper buys sugar at ₹48 per kg. While selling, he uses a faulty weighing scale that gives only 960 g instead of 1 kg. In addition, he marks the selling price at a profit of 20% on the cost price and then offers a discount of 10% on the marked price. Find the overall percentage profit or loss made by the shopkeeper.
A trader sells rice, claiming 1 kg but actually gives x grams. He marks the price 20% above the cost price and gives a 10% discount on the marked price. If his overall profit is 25%, find x.
A dishonest shopkeeper professes to sell his goods at a 35% loss but uses a false balance and gains 85%. The actual weight (rounded off to one decimal place) he uses for 1 kg is:
A merchant buys tea at ₹100 per kg and sells it using a 800 g weight as 1 kg, after marking the price up by 25% and giving a discount of 20%. What is his profit per kg?
A shopkeeper marks the price of sugar 24% above the cost price and gives a discount of 18%, but uses a weight of 800 grams instead of 1 kg. Find his overall profit percentage.
A fruit seller uses a faulty balance that reads 900 grams as 1 kg. He sells apples at ₹150 per kg (as per faulty balance). If his purchase price is ₹120 per kg (actual weight), what is his actual profit percentage?
A trader claims to sell fruits at a profit of 22%, but also dishonestly uses a weight which is 4% less than what is mentioned on it. Find the total percentage of profit earned by the trader. (Round off the answer to the nearest whole number.)